Solving Systems using substitution

Solve the system of equations by substitution.
y = -4x + 5
y =  3x - 16

• (-3, -25)
• (3,-7)
• (11, 17)
• (21, 47)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

y = -6
-3x - 6y = 24

• (6, 6)
• (6, -6)
• (4, -6)
• (-6, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution?

• (1, -1)
• (-1, 1)
• (0, -2)
• (0, 1)

Tags

CCSS.8.EE.C.8B

Solve:
x = -3y - 17
2x + 3y = -7

• (1, -20)
• (3, 0)
• (-5, -2)
• (10 , -9)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

The first step in solving using the substitution method is __________.

• get x by itself

• get y by itself

• get either variable by itself in one equation

• add the equations together

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using substitution:
-4x + 4y = 8
y = -2x - 10

• (-4, -2)
• (12, -34)
• (4, -18)
• (-2, -6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

How many solutions will this system have?

• No Solution
• Infinitely Many Solutions
• No Clue
• One solution

Tags

CCSS.8.EE.C.8A

Solve:

y = 7x + 7

2y + 2x = -18

• (5, 0)

• (9, 18)

• (-2, -7)

• (1, 16)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

6x = y

3y - 4x = 42

• (3, 18)

• (8, 2)

• (2, 8)

• (1, 6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• No Solution

• (2, 2)

• (-1, 2)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6