MATH 9 - REVIEW QUIZ FOR 1ST QT

What is the standard form of the quadratic equation?

• ax² = bx + c

• ax² – bx = c

• ax² + bx + c = 0

• bx + c = ax²

Which quadratic equation has the following values: a = 1, b = 2, c = –4?  

• x² + 4x + 2 = 0

• x² – 4x + 2 = 0

• x² + 2x + 4 = 0

• x² + 2x – 4 = 0

The length of a rectangle is 2 inches more than its width (w). The area of the rectangle is 91 square inches. Which quadratic equation expresses this problem? Hint: Area = length width

• (w+2) * (w) = 91   

• (2w)*(w)=91

• (w-2) * (w) = 91

• (w+2)*(w+2)=91

The square of a number is 81. What is the number?

• 3

• 6

• 9

• 12

Which of the following quadratic equations has the solutions of ±8?

• x² = – 64

• x² = 64

• x² = – 16

• x² = 16

If the area of a square tile is v² − 144, what is its dimensions?

• (v + 12) (v – 12)

• (v + 12) (v + 12)

• (v – 12) (v – 12)

• (v – 12)²

A rectangular garden has an area of 48 square meters. The length of the garden is 2 meters more than its width. Which are the correct dimensions of the garden? Hint: A = (length) (width)

• l = 8 m, w = 6m

• l = 4m, w = 2m

• l = 6m, w = 4m

• l = 8m, w = 4m

A student solves the quadratic equation x² – 20x + 19 = 0, gets the factors (x – 19) and (x – 1); and the roots x = – 19 and x = – 1. Evaluate the accuracy of this student's solution.

• The solution is correct.

• The solution is incorrect because the correct roots are x = 19 and x = – 1.

• The solution is incorrect because the correct roots are x = 19 and x = 1.

• The solution is incorrect because the correct roots are x = – 19 and x = 1.

Two students used different methods to solve the equation x² + 6x + 9 = 0. Student A factored the equation, and Student B used the quadratic formula. Both of them arrived at x = – 3. Evaluate their approaches.

• Student B’s use of the quadratic formula is unnecessary, but the solution is correct.

• Both students' approaches are correct because both methods will result at the correct answer.

• Neither student's approach is appropriate for this type of equation.

• Student A’s factoring method is incorrect.

Which expression is equal to a discriminant value 36?

• 4² – 4(1)(-5)

• 4² – 4(-2)(-4)

• 4² – 4(2)(-5)     

• .  4² – 4(1)(5)