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Subnetting Workbook

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Subnetting Workbook
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91 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Fill in the blank: An IP address is made up of four numbers called ______ separated by dots.

octets

bytes

segments

blocks

Answer explanation

An IP address consists of four numbers, each ranging from 0 to 255, known as octets. They are separated by dots, making 'octets' the correct term, while 'bytes', 'segments', and 'blocks' are not used in this context.

2.

OPEN ENDED QUESTION

3 mins • 1 pt

What does the subnet mask 255.255.255.0 indicate?

Evaluate responses using AI:

OFF

Answer explanation

The subnet mask 255.255.255.0 indicates a Class C network, allowing for 256 IP addresses (0-255) in the subnet, with 254 usable for hosts. It defines the first 24 bits as the network part and the last 8 bits for host addresses.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the subnet mask example given in the Subnetting Workbook?

255.255.255.0

255.255.0.0

255.0.0.0

255.255.255.255

Answer explanation

The subnet mask 255.255.255.0 is commonly used for Class C networks, allowing for 256 IP addresses in a subnet. This makes it the correct choice in the Subnetting Workbook example.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The network 192.168.1.0 can be split into two smaller networks by:

Using a subnet mask of 255.255.255.128

Using a subnet mask of 255.255.255.0

Using a subnet mask of 255.255.255.192

Using a subnet mask of 255.255.255.224

Answer explanation

Using a subnet mask of 255.255.255.128 allows the 192.168.1.0 network to be divided into two smaller networks (192.168.1.0/25 and 192.168.1.128/25), effectively splitting the original network.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many computers can be accommodated in the network 192.168.1.0 with the subnet mask 255.255.255.0?

254

256

255

253

Answer explanation

The subnet mask 255.255.255.0 allows for 256 total IP addresses. However, 2 addresses are reserved (network and broadcast), leaving 254 usable addresses for computers in the network 192.168.1.0.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given network: 192.168.2.0 Current subnet mask: 255.255.255.0 Task: Split this network into two subnets. What will be the network address for each subnet?

192.168.2.0 and 192.168.2.128

192.168.2.0 and 192.168.2.64

192.168.2.0 and 192.168.2.32

192.168.2.0 and 192.168.2.16

Answer explanation

To split the 192.168.2.0/24 network into two subnets, we borrow one bit from the host part, resulting in a /25 subnet mask (255.255.255.128). This gives us two subnets: 192.168.2.0 and 192.168.2.128.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given network: 192.168.2.0 Current subnet mask: 255.255.255.0 Task: Split this network into two subnets. 2. What will be the first and last usable address in each subnet?

Subnet 1: 192.168.2.1 to 192.168.2.126, Subnet 2: 192.168.2.129 to 192.168.2.254

Subnet 1: 192.168.2.1 to 192.168.2.62, Subnet 2: 192.168.2.65 to 192.168.2.126

Subnet 1: 192.168.2.1 to 192.168.2.126, Subnet 2: 192.168.2.128 to 192.168.2.254

Subnet 1: 192.168.2.1 to 192.168.2.64, Subnet 2: 192.168.2.65 to 192.168.2.128

Answer explanation

To split 192.168.2.0/24 into two subnets, we use a /25 subnet mask (255.255.255.128). This gives us Subnet 1: 192.168.2.0/25 (usable 192.168.2.1 to 192.168.2.126) and Subnet 2: 192.168.2.128/25 (usable 192.168.2.129 to 192.168.2.254).

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