TIẾT 89. LUYỆN TẬP GIẢI BPT BẬC HAI MỘT ẨN

⊘

ℝ

(1;3)

(−∞; −1] ⋃ [3; +∞)

$$\left(-\infty;-\frac{3}{2}\right]\cup\left[5;+\infty\right)$$

$$\left[-\frac{3}{2};\ 5\right]$$

$$\left(-\infty;-5\right]\cup\left[\frac{3}{2};+\infty\right)$$

$$\left[-\ 5;\frac{3}{2}\right]$$

[1; 4]

(1; 4)

$$\left(-\infty;\ 1\right)\cup\left(4;+\infty\right)$$

$$\left(-\infty;\ 1\right]\cup\left[4;+\infty\right)$$

2

3

4

5

$$-3x^2+x-1\ge0$$

$$-3x^2+x-1>0$$

$$-3x^2+x-1\le0$$

$$-3x^2+x-1<0$$

6

5

4

2

$$x^2+2x+1<0$$

$$x^2+2x+3\le0$$

$$x^2+3x+4<0$$

$$x^2-2x+1\le0$$

$$x^2+2x\ge0$$

$$x^2+2x+3\le0$$

$$x^2-4<0$$

$$x^2>0$$

$$3x^2-12x+1>0$$

$$x^3-5x+1<0$$

$$x^2-4x+1=0$$

$$-9x+1>0$$

5

2

7

$$-1$$