
Linear and Exponential Equations
Authored by Steven Pavlakis
Mathematics
9th Grade
CCSS covered
Used 2+ times

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31 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
The equation of a line in point-slope form is y - y1 = m(x - x1). Here, m = -2/3 and the point is (3, 2). Substituting these values gives y - 2 = -2/3(x - 3), which simplifies to y = 2 - (2/3)(x - 3).
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.LE.A.2
CCSS.HSF.BF.A.1
CCSS.HSA.CED.A.2
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Answer explanation
To find the equation, use the point-slope form: y - y1 = m(x - x1). Here, m = 4 and the point is (-5, 10). Plugging in gives y - 10 = 4(x + 5), which simplifies to y = 10 + 4(x + 5). Thus, the correct choice is y=10+4(x+5).
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.LE.A.2
CCSS.HSF.BF.A.1
CCSS.HSA.CED.A.2
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Write the equation of the linear or exponential function that best models the given information:
The starting point is (1, 5) and the output values are multiplied by 3 each time.
Answer explanation
The function starts at (1, 5) and multiplies by 3 each time, indicating an exponential growth. The correct model is y=5(3)^(x-1), where 5 is the initial value and 3 is the growth factor.
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.LE.A.2
CCSS.HSF.BF.A.1
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Write the equation of the linear or exponential function that best models the given information:
The starting point is (3, 400) and the output values are divided by 2 each time.
Answer explanation
The function starts at (3, 400) and halves the output each time, indicating an exponential decay. The correct model is y=400(1/2)^(x-3), which reflects the starting point and the halving behavior.
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.LE.A.2
CCSS.HSF.BF.A.1
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Write the equation of the linear or exponential function that best models the given information:
A line goes through the points (-3, 2) and a slope of 3.
Answer explanation
To find the equation of the line, use the point-slope form: y - y1 = m(x - x1). Here, m = 3 and the point (-3, 2) gives y - 2 = 3(x + 3). Rearranging leads to y = 2 + 3(x + 3), which matches the correct choice.
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.BF.A.1
CCSS.HSF.IF.A.1
CCSS.HSA.CED.A.1
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Write the equation of the linear or exponential function that best models the given information:
A line goes through the points (5, -10) and (-3, 2).
Answer explanation
To find the equation of the line through (5, -10) and (-3, 2), we calculate the slope as m = (2 - (-10)) / (-3 - 5) = 3/2. Using point-slope form, we get y + 10 = -3/2(x - 5), simplifying to y = -10 - (3/2)(x - 5).
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.LE.A.2
CCSS.HSF.BF.A.1
CCSS.HSA.CED.A.2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Write the equation of the linear or exponential function that best models the given information:
Answer explanation
The correct choice is y=5+\frac{7}{2}(x+3) because it represents a linear function with a slope of \frac{7}{2} and a y-intercept adjusted by 5, fitting the given data points accurately.
Tags
CCSS.HSF.LE.A.1
CCSS.HSF.LE.A.2
CCSS.HSF.BF.A.1
CCSS.HSA.CED.A.2
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