Linear Functions Review

Linear Functions Review

9th Grade

25 Qs

quiz-placeholder

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Linear Functions Review

Linear Functions Review

Assessment

Quiz

Mathematics

9th Grade

Practice Problem

Medium

Created by

Anjali Mudgal

Used 2+ times

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25 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What is the formula for finding slope of the line containing  (x1, y1) and (x2, y2)\left(x_1,\ y_1\right)\ and\ \left(x_2,\ y_2\right)  ?

m=y2y1x2x1m=\frac{y_2-y_1}{x_2-x_1}

m=x2x1y2y1m=\frac{x_2-x_1}{y_2-y_1}

m=y2y1x1x2m=\frac{y_2-y_1}{x_1-x_2}

m=y1y2x2x1m=\frac{y_1-y_2}{x_2-x_1}

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the slope of the line that contains the given points:

 (2,3) and (5,1)\left(2,-3\right)\ and\ \left(5,-1\right)  

 23\frac{2}{3}  

 32\frac{3}{2}  

 23-\frac{2}{3}  

 32-\frac{3}{2}  

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the slope of the line that contains the given points:

 (3,9) and (3,11)\left(3,-9\right)\ and\ \left(3,11\right)  

 00  

Undefined

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the slope of the line that contains the given points:

 (4,12) and (4,12)\left(4,12\right)\ and\ \left(-4,12\right)  

undefined

 00  

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the equation of a line in Point-Slope Form that has the given properties:


 m=12 through (5,6)m=-\frac{1}{2}\ through\ \left(-5,6\right)  

 y6=12(x+5)y-6=-\frac{1}{2}\left(x+5\right)  

 y+6=12(x5)y+6=-\frac{1}{2}\left(x-5\right)  

 y+5=12(x6)y+5=-\frac{1}{2}\left(x-6\right)  

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Find the equation of the line that contains the following conditions, in SLOPE-INTERCEPT Form:

 m=3 through (2,5)m=3\ through\ \left(2,-5\right)  



 y=3x11y=3x-11  

 y+5=3(x2)y+5=3\left(x-2\right)  

 y=3x1y=3x-1  

 y=3x+14y=3x+14  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt


Find the equation of the line that contains the following points in SLOPE-INTERCEPT Form:

 m=12 through (8,1)m=\frac{1}{2}\ through\ \left(8,-1\right)  

 y=12x5y=\frac{1}{2}x-5  

 y+1=12(x8)y+1=\frac{1}{2}\left(x-8\right)  

 y=12x3y=\frac{1}{2}x-3  

 y=12x+4y=\frac{1}{2}x+4  

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