What is the equilibrium constant for the reaction of oxalic acid at 25 degrees Celsius?

Equilibrium Constants in Chemical Reactions

Interactive Video
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Chemistry, Science
•
10th - 12th Grade
•
Hard

Jackson Turner
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
3.8 x 10^-6
2.6 x 10^5
6.8 x 10^-4
4.6 x 10^-7
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How does reversing a reaction affect its equilibrium constant?
It squares the constant
It doubles the constant
It halves the constant
It inverts the constant
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the equilibrium constant for the reverse reaction of oxalic acid at 25 degrees Celsius?
2.6 x 10^5
4.6 x 10^-7
3.8 x 10^-6
6.8 x 10^-4
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the new equilibrium constant when the hydrofluoric acid reaction is multiplied by a factor of two?
4.6 x 10^-7
2.6 x 10^5
3.8 x 10^-6
6.8 x 10^-4
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the equilibrium constant if a reaction is multiplied by a factor of three?
It is inverted
It is squared
It is cubed
It remains unchanged
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the equilibrium constant for the ionization of hydrofluoric acid at 25 degrees Celsius?
2.6 x 10^5
3.8 x 10^-6
4.6 x 10^-7
6.8 x 10^-4
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in calculating the equilibrium constant for a new reaction formed by combining two reactions?
Add the equilibrium constants
Subtract the equilibrium constants
Reverse the first reaction
Multiply the equilibrium constants
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