Understanding Spherical Mirrors

Understanding Spherical Mirrors

Assessment

Interactive Video

Physics, Science

9th - 12th Grade

Practice Problem

Hard

Created by

Jackson Turner

FREE Resource

This video tutorial focuses on solving problems related to spherical mirrors, specifically concave mirrors. It begins with an introduction to the concepts of focal length and radius of curvature. The video then demonstrates how to draw ray diagrams to locate images formed by concave mirrors. It explains the mirror equation and how to calculate image location and magnification. Two example problems are solved, illustrating the process of determining whether an image is real or virtual, inverted or upright, and enlarged or reduced.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the radius of curvature of a concave mirror if its focal length is 10 cm?

15 cm

5 cm

10 cm

20 cm

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a ray diagram for a concave mirror, what does it mean if the light rays actually converge?

The image is real

The image is virtual

The image is upright

The image is reduced

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the focal length if the radius of curvature is known?

Subtract 10 from the radius

Add 10 to the radius

Divide the radius by 2

Multiply the radius by 2

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does a negative magnification indicate about the image?

The image is reduced

The image is virtual

The image is inverted

The image is upright

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the magnification of an image is greater than 1, what can be said about the image?

The image is the same size

The image is enlarged

The image is virtual

The image is reduced

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the new problem, what is the focal length of the concave mirror?

15 cm

20 cm

10 cm

5 cm

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the nature of the image if the image distance (di) is negative?

The image is reduced

The image is inverted

The image is virtual

The image is real

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