Solving Radical Equations Concepts

Solving Radical Equations Concepts

Assessment

Interactive Video

Mathematics

8th - 10th Grade

Practice Problem

Medium

CCSS
HSA.REI.A.2, HSA-REI.B.4B, HSA.APR.C.4

+2

Standards-aligned

Created by

Emma Peterson

Used 7+ times

FREE Resource

Standards-aligned

CCSS.HSA.REI.A.2
,
CCSS.HSA-REI.B.4B
,
CCSS.HSA.APR.C.4
CCSS.6.EE.B.5
,
CCSS.6.EE.B.6
,
The video tutorial covers solving a complex radical equation with radicals on both sides. The instructor demonstrates isolating the radicals, squaring both sides of the equation twice, and simplifying to find potential solutions. After solving, the instructor checks the solutions to determine their validity, concluding that the equation has no valid solutions. The lesson ends with instructions for classwork and homework assignments.

Read more

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving an equation with radicals on both sides?

Add a constant to both sides

Isolate one of the radicals

Subtract a constant from both sides

Multiply both sides by a constant

Tags

CCSS.HSA.REI.A.2

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After isolating a radical, what operation is performed to eliminate it?

Squaring both sides

Taking the cube root

Adding a constant

Dividing by a constant

Tags

CCSS.HSA.APR.C.4

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of squaring the expression (sqrt(x) - 4)?

x - 8sqrt(x) + 16

x + 8sqrt(x) + 16

x - 4

x + 16

Tags

CCSS.HSA-REI.B.4B

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after obtaining the equation x = x^2 - 4x + 4?

Add x to both sides

Subtract x from both sides

Divide both sides by x

Multiply both sides by x

Tags

CCSS.HSA-REI.B.4B

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following is a potential solution to the equation x^2 - 5x + 4 = 0?

x = 5

x = 3

x = 2

x = 4

Tags

CCSS.HSA.REI.A.2

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why is x = 4 not a valid solution for the original equation?

It results in an undefined value

It results in a positive value

It results in a zero value

It results in a negative value

Tags

CCSS.6.EE.B.5

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the outcome when x = 1 is substituted back into the original equation?

The equation holds true

The equation does not hold true

The equation results in a negative value

The equation results in a positive value

Tags

CCSS.HSA.REI.A.2

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