
Solving Radical Equations Concepts
Interactive Video
•
Mathematics
•
8th - 10th Grade
•
Practice Problem
•
Medium
+2
Standards-aligned
Emma Peterson
Used 9+ times
FREE Resource
Standards-aligned
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10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step in solving an equation with radicals on both sides?
Add a constant to both sides
Isolate one of the radicals
Subtract a constant from both sides
Multiply both sides by a constant
Tags
CCSS.HSA.REI.A.2
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
After isolating a radical, what operation is performed to eliminate it?
Squaring both sides
Taking the cube root
Adding a constant
Dividing by a constant
Tags
CCSS.HSA.APR.C.4
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the result of squaring the expression (sqrt(x) - 4)?
x - 8sqrt(x) + 16
x + 8sqrt(x) + 16
x - 4
x + 16
Tags
CCSS.HSA-REI.B.4B
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step after obtaining the equation x = x^2 - 4x + 4?
Add x to both sides
Subtract x from both sides
Divide both sides by x
Multiply both sides by x
Tags
CCSS.HSA-REI.B.4B
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is a potential solution to the equation x^2 - 5x + 4 = 0?
x = 5
x = 3
x = 2
x = 4
Tags
CCSS.HSA.REI.A.2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Why is x = 4 not a valid solution for the original equation?
It results in an undefined value
It results in a positive value
It results in a zero value
It results in a negative value
Tags
CCSS.6.EE.B.5
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the outcome when x = 1 is substituted back into the original equation?
The equation holds true
The equation does not hold true
The equation results in a negative value
The equation results in a positive value
Tags
CCSS.HSA.REI.A.2
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