Light Intensity and Polarization Concepts

This video tutorial covers the concept of light polarization and how to calculate the intensity of light passing through polarizing filters. It includes several practice problems that demonstrate the application of Malus's Law to determine the intensity of light after passing through one or more filters at various angles. The tutorial also explores the relationship between amplitude and intensity, and how different filter orientations affect light transmission.

What happens to the intensity of unpolarized light after it passes through the first polarizing filter?

• It doubles.

• It remains the same.

• It becomes zero.

• It is reduced by half.

How do you calculate the intensity of light after it passes through a second polarizing filter at an angle?

• Multiply by the sine of the angle.

• Multiply by the cosine squared of the angle.

• Divide by the cosine of the angle.

• Add the angle to the initial intensity.

If two polarizing filters are oriented at 90 degrees to each other, what is the intensity of light emerging from the second filter?

• It is the same as the initial intensity.

• It is half of the initial intensity.

• It is zero.

• It is double the initial intensity.

What effect does adding a third filter at 45 degrees between two filters at 90 degrees have on the light intensity?

• It decreases the intensity to zero.

• It increases the intensity from zero to a higher value.

• It doubles the intensity.

• It has no effect on the intensity.

When light is already polarized, how do you calculate the intensity after it passes through a filter?

• Divide the initial intensity by two.

• Multiply the initial intensity by the sine of the angle.

• Use Malus's Law with the angle between the light and the filter.

• Add the angle to the initial intensity.

What is the reduction in intensity when light polarized at 21 degrees passes through a filter at 42 degrees?

• 12.84%

• 0%

• 87.16%

• 51.86%

How is the amplitude of light related to its intensity?

• Amplitude is half of intensity.

• Intensity is the square root of amplitude.

• Intensity is proportional to the square of amplitude.

• Amplitude is the square of intensity.

What is the amplitude of light emerging from the first filter if the initial amplitude is A0?

• A0 * 2

• A0 * sqrt(2)/2

• A0/2

• A0

If the second filter is at a 10-degree angle counterclockwise to the first, what is the angle difference used in calculations?

• 15 degrees

• 10 degrees

• 5 degrees

• 25 degrees

What is the final amplitude of light after passing through three filters with initial amplitude A0?

• A0

• 0.619 A0

• 0.6409 A0

• 0.8716 A0