Diketahui vektor u → = 4 i → + 2 j → \overrightarrow{u\ }=4\ \overrightarrow{i\ }+\ 2\ \overrightarrow{j\ } u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 4 i <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 2 j <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> maka ∣ u → ∣ = . . . \left|\overrightarrow{u\ }\right|\ =\ ... ∣ ∣ ∣ u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ∣ ∣ ∣ = . . .

2 5 2\sqrt{5} 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 \sqrt{6} 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 \sqrt{5} 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 3 3\sqrt{3} 3 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 2 3\sqrt{2} 3 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

PENILAIAN VEKTOR: 15 Latihan Soal Kelas 10

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A = 5i + 7j , B = -6i + 2j maka
B - A = ...

-i + 9j

11i + 5j

-11i + 9j

5i + 11j

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Vektor PQ adalah ... .

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

|a| = 11

|a| = 13

|a| = 15

|a| = 17

|a| = 19

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Seorang anak berjalan lurus 2 meter ke barat, kemudian belok ke selatan sejauh 6 meter, dan belok lagi ke timur sejauh 10 meter. Perpindahan yang dilakukan anak tersebut dari posisi awal ….

18 meter arah barat daya

14 meter arah selatan

10 meter arah tenggara

meter arah timur

2 meter arah tenggara

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Diketahui vektor pada R3 berikut:
a = 8 i - 4 j + 3 k
b = 3 i - 2 j
c = - i - 5 j + 7 k

Hasil dari 2a - b + 3c adalah ...

13 i + 4 j + 29 k

13 i - 26 j + 29 k

13 i + 26 j + 25 k

10 i + 9 j + 27 k

10 i -21 j + 27 k

8.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Diketahui dua buah vektor seperti berikut.

Hasil dari $\overrightarrow{a\ }\ -\overrightarrow{b\ }$ yang benar dengan metode segitiga adalah ....

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PENILAIAN VEKTOR

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

A = 5i + 7j , B = -6i + 2j maka
B - A = ...

Vektor PQ adalah ... .

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

Seorang anak berjalan lurus 2 meter ke barat, kemudian belok ke selatan sejauh 6 meter, dan belok lagi ke timur sejauh 10 meter. Perpindahan yang dilakukan anak tersebut dari posisi awal ….

Diketahui vektor pada R3 berikut:
a = 8 i - 4 j + 3 k
b = 3 i - 2 j
c = - i - 5 j + 7 k

Hasil dari 2a - b + 3c adalah ...

Diketahui dua buah vektor seperti berikut.

Hasil dari $\overrightarrow{a\ }\ -\overrightarrow{b\ }$ yang benar dengan metode segitiga adalah ....

A (-3,8) dan B (-5,2) maka
A + 2B = ...

A (0,2) dan B (5,3) maka
3A - 2B = ...

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

PENILAIAN VEKTOR

misal suatu vektor secara komponen ditulis seperti gambar diatas, maka penulisan dalam bentuk analitis adalah...

A = 5i + 7j , B = -6i + 2j maka B - A = ...

Vektor PQ adalah ... .

Jika vektor a = 12 i + 5 k . ﻿Maka panjang vektor a adalah ...

Diketahui koordinat titik K(2,3) dan Titik L(-3,7). Vektor KL adalah .....

Seorang anak berjalan lurus 2 meter ke barat, kemudian belok ke selatan sejauh 6 meter, dan belok lagi ke timur sejauh 10 meter. Perpindahan yang dilakukan anak tersebut dari posisi awal ….

Diketahui vektor pada R3 berikut: a = 8 i - 4 j + 3 kb = 3 i - 2 jc = - i - 5 j + 7 kHasil dari 2a - b + 3c adalah ...

Diketahui dua buah vektor seperti berikut. Hasil dari a → −b →\overrightarrow{a\ }\ -\overrightarrow{b\ }a −b yang benar dengan metode segitiga adalah ....

A (-3,8) dan B (-5,2) maka A + 2B = ...

A (0,2) dan B (5,3) maka 3A - 2B = ...

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

A = 5i + 7j , B = -6i + 2j maka
B - A = ...

Jika vektor a = 12 i + 5 k .

Maka panjang vektor a adalah ...

Diketahui vektor pada R3 berikut:
a = 8 i - 4 j + 3 k
b = 3 i - 2 j
c = - i - 5 j + 7 k

Hasil dari 2a - b + 3c adalah ...

Diketahui dua buah vektor seperti berikut.

Hasil dari $\overrightarrow{a\ }\ -\overrightarrow{b\ }$ yang benar dengan metode segitiga adalah ....

A (-3,8) dan B (-5,2) maka
A + 2B = ...

A (0,2) dan B (5,3) maka
3A - 2B = ...