Diketahui koordinat titik A (- 2, 5) dan B (7, - 3). Vektor A B → = . . . . . \overrightarrow{AB\ }=..... A B <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = . . . . .

( 9 − 8 ) \left(9\ \ \ \ \ -8\right) ( 9 − 8 )

( 9 8 ) \left(9\ \ \ \ \ \ 8\right) ( 9 8 )

( − 9 − 8 ) \left(-9\ \ \ \ \ -8\right) ( − 9 − 8 )

( − 9 8 ) \left(-9\ \ \ \ \ 8\right) ( − 9 8 )

( 5 2 ) \left(5\ \ \ \ \ 2\right) ( 5 2 )

Diketahui a → = − 5 i + 2 j , b → = − 3 i + 2 j \overrightarrow{a}=-5i+2j,\ \overrightarrow{b}=-3i+2j a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − 5 i + 2 j , b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = − 3 i + 2 j dan c → = 3 i − 7 j \overrightarrow{c}=3i-7j c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 3 i − 7 j . Maka nilai 3 c → − a → + 2 b → 3\overrightarrow{c}-\overrightarrow{a}+2\overrightarrow{b} 3 c <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> − a <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 2 b <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> adalah . . . . .

8 i − 19 j 8i-19j 8 i − 1 9 j

− 8 i − 19 j -8i-19j − 8 i − 1 9 j

− 8 i + 19 j -8i+19j − 8 i + 1 9 j

Tentukan Vektor-Vektor pada Gambar 2 dalam ungkapan Vektor satuan

∣P∣=3i+3j dan ∣Q∣=-5i-3j

∣P∣=3i-3j dan ∣Q∣=-5i+3j

∣P∣=3i+3j dan ∣Q∣=-5i-3j

∣P∣=-3i+3j dan ∣Q∣=5i+3j

∣P∣=-3i-3j dan ∣Q∣=-5i-3j

Diketahui vektor u → = 4 i → + 2 j → \overrightarrow{u\ }=4\ \overrightarrow{i\ }+\ 2\ \overrightarrow{j\ } u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> = 4 i <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> + 2 j <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> maka ∣ u → ∣ = . . . \left|\overrightarrow{u\ }\right|\ =\ ... ∣ ∣ ∣ u <path d="M0 241v40h399891c-47.3 35.3-84 78-110 128 -16.7 32-27.7 63.7-33 95 0 1.3-.2 2.7-.5 4-.3 1.3-.5 2.3-.5 3 0 7.3 6.7 11 20 11 8 0 13.2-.8 15.5-2.5 2.3-1.7 4.2-5.5 5.5-11.5 2-13.3 5.7-27 11-41 14.7-44.7 39-84.5 73-119.5s73.7-60.2 119-75.5c6-2 9-5.7 9-11s-3-9-9-11c-45.3-15.3-85 -40.5-119-75.5s-58.3-74.8-73-119.5c-4.7-14-8.3-27.3-11-40-1.3-6.7-3.2-10.8-5.5 -12.5-2.3-1.7-7.5-2.5-15.5-2.5-14 0-21 3.7-21 11 0 2 2 10.3 6 25 20.7 83.3 67 151.7 139 205zm0 0v40h399900v-40z"> ∣ ∣ ∣ = . . .

2 5 2\sqrt{5} 2 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

6 \sqrt{6} 6 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

5 \sqrt{5} 5 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 3 3\sqrt{3} 3 3 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

3 2 3\sqrt{2} 3 2 <path d="M95,702c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5, -10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8, -50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0, 35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5, -221c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467 s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422 s-65,47,-65,47z M834 80H400000v40H845z">

LATIHAN SOAL PAS GASAL 2024 Kuis

30 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 8 pts

Hasil dari $\frac{8^{2x-1}\ \times\ 2^{x-3}}{4\ \times\ 4^{2-x}}$ adalah... .

$2^{9x+12}$

$2^{5x}$

$2^{9x-12}$

$2^{5x-1}$

2.

MULTIPLE CHOICE QUESTION

5 mins • 7 pts

Berapa nilai x dari $3^{\ 5x-3}\ =\ 9^{\ x+3}$ ... .

4

1

2

3

3.

MULTIPLE CHOICE QUESTION

5 mins • 10 pts

Rasionalkan penyebut pecahan berikut
$\frac{\sqrt[]{7}\ -\ \sqrt[]{2}}{\sqrt[]{7}\ +\ \sqrt[]{2}}$

$\frac{9\ -\ \sqrt[]{28}}{5}$

$\frac{9}{5}$

$\frac{9\ -\ 14\ \sqrt[]{2}}{5}$

$\frac{9\ -\ 2\ \sqrt[]{14}}{5}$

4.

MULTIPLE CHOICE QUESTION

5 mins • 12 pts

Hasil dari $\left(\frac{3a^{-2}b^3c^4}{15a^3b^{-5}c^{-2}}\right)^{-1}$ adalah ... .

$5a^5b^{-8}c^{-6}$

$5ab^{-2}c^{-6}$

$5b^{-2}c^{-6}$

$5ab^{-2}c^2$

5.

MULTIPLE CHOICE QUESTION

5 mins • 15 pts

Dani berlari dilapangan desa yang berbentuk persegi panjang dengan lebar $2\ \sqrt[]{20}$ dan panjang $4\ +\ 3\ \sqrt[]{5}$ .
Berapakah keliling dari lapangan tersebut?

$4\ +\ 7\ \sqrt[]{10}$

$8\ +\ 14\ \sqrt[]{5}$

$8\ +\ 14\ \sqrt[]{10}$

$4\ +\ 7\ \sqrt[]{5}$

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Nilai dari ²log16 - ³log27 + ⁵log1 = ....

-1

0

1

2

3

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

²log 8

1

2

3

4

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LATIHAN SOAL PAS GASAL 2024

Hasil dari $\frac{8^{2x-1}\ \times\ 2^{x-3}}{4\ \times\ 4^{2-x}}$ adalah... .

Berapa nilai x dari $3^{\ 5x-3}\ =\ 9^{\ x+3}$ ... .

Rasionalkan penyebut pecahan berikut
$\frac{\sqrt[]{7}\ -\ \sqrt[]{2}}{\sqrt[]{7}\ +\ \sqrt[]{2}}$

Hasil dari $\left(\frac{3a^{-2}b^3c^4}{15a^3b^{-5}c^{-2}}\right)^{-1}$ adalah ... .

Dani berlari dilapangan desa yang berbentuk persegi panjang dengan lebar $2\ \sqrt[]{20}$ dan panjang $4\ +\ 3\ \sqrt[]{5}$ .
Berapakah keliling dari lapangan tersebut?

Nilai dari ²log16 - ³log27 + ⁵log1 = ....

²log 8

⁴log 64= ....

Hasil dari ²log 9 . ⁹log 6 . ⁶log 16 adalah ...

Suku ke-3 dan suku ke-8 suatu barisan aritmatika berturut-turut adaalah 20 dan 40. Suku pertama dan beda dari barisan ini berturut-turut adalah ....

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LATIHAN SOAL PAS GASAL 2024

Hasil dari 82x−1 × 2x−34 × 42−x\frac{8^{2x-1}\ \times\ 2^{x-3}}{4\ \times\ 4^{2-x}}4 × 42−x82x−1 × 2x−3​ adalah... .

Berapa nilai x dari 3 5x−3 = 9 x+33^{\ 5x-3}\ =\ 9^{\ x+3}3 5x−3 = 9 x+3 ... .

Rasionalkan penyebut pecahan berikut 7 − 27 + 2\frac{\sqrt[]{7}\ -\ \sqrt[]{2}}{\sqrt[]{7}\ +\ \sqrt[]{2}}7​ + 2​7​ − 2​​

Hasil dari (3a−2b3c415a3b−5c−2)−1\left(\frac{3a^{-2}b^3c^4}{15a^3b^{-5}c^{-2}}\right)^{-1}(15a3b−5c−23a−2b3c4​)−1 adalah ... .

Dani berlari dilapangan desa yang berbentuk persegi panjang dengan lebar 2 202\ \sqrt[]{20}2 20​ dan panjang 4 + 3 54\ +\ 3\ \sqrt[]{5}4 + 3 5​ . Berapakah keliling dari lapangan tersebut?

Nilai dari 2log16 - 3log27 + 5log1 = ....

²log 8

4log 64= ....

Hasil dari 2log 9 . 9log 6 . 6log 16 adalah ...

Suku ke-3 dan suku ke-8 suatu barisan aritmatika berturut-turut adaalah 20 dan 40. Suku pertama dan beda dari barisan ini berturut-turut adalah ....

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Discover more resources for Mathematics

Hasil dari $\frac{8^{2x-1}\ \times\ 2^{x-3}}{4\ \times\ 4^{2-x}}$ adalah... .

Berapa nilai x dari $3^{\ 5x-3}\ =\ 9^{\ x+3}$ ... .

Rasionalkan penyebut pecahan berikut
$\frac{\sqrt[]{7}\ -\ \sqrt[]{2}}{\sqrt[]{7}\ +\ \sqrt[]{2}}$

Hasil dari $\left(\frac{3a^{-2}b^3c^4}{15a^3b^{-5}c^{-2}}\right)^{-1}$ adalah ... .

Dani berlari dilapangan desa yang berbentuk persegi panjang dengan lebar $2\ \sqrt[]{20}$ dan panjang $4\ +\ 3\ \sqrt[]{5}$ .
Berapakah keliling dari lapangan tersebut?

Nilai dari ²log16 - ³log27 + ⁵log1 = ....

⁴log 64= ....

Hasil dari ²log 9 . ⁹log 6 . ⁶log 16 adalah ...