Quiz Kimia Semester Ganjil
Quiz
•
Chemistry
•
12th Grade
•
Practice Problem
•
Hard
Nurmariana Okto Delima Sinaga
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74 questions
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1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
20% Glikol (Mr=62). Jika nilai Kb air = 0,52 dan Kf air= 1,86, titik didih dan titik beku larutan berturut-turut adalah….
102oC dan -7,5oC
103oC dan -8,5oC
104oC dan -9,5oC
105oC dan -10,5oC
106oC dan -11,5oC
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Larutan A mengandung 0,02 mol K2SO4 yang terionisasi sempurna dalam 200 gram air. Larutan B mengandung sejumlah sukrosa (Mr=342) dalam 500 gram air. Perubahan titik beku larutan gula adalah setengah perubahan titik beku larutan A. Nilai Kf adalah 1,86 oC mol g-1. Massa sukrosa dalam larutan B adalah….
25,65 gram
20,56 gram
12,825 gram
8,55 gram
5,13 gram
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Sebanyak 12,4 g etilen glikol, C2H4(OH)2 dan 19 g MgCl2 dilarutkan dalam 250 ml air. Jika Kf air adalah 1,8oC/m, titik beku larutan tersebut adalah….(Ar C=12; H=1; O=16; Mg=24; Cl=35,5)
-2,16oC
-3,06oC
-3,96oC
-4,86oC
-5,76oC
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Berikut adalah pernuyataan yang tepat tentang konsep reduksi-oksidasi….
Pengikatan oksigen dan penerimaan elektron
Pengikatan oksigen dan pelepasan elektron
Pelepasan oksigen dan penerimaan elektron
Pengikatan oksigen dan penurunan bilangan oksidasi
Pelepasan oksigen dan pelepasan elektron
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Bilangan oksidasi Al dalam Al2O3, Cr dalam Cr2O72-, dan P dalam H3PO4 berturut-turut adalah....
+2, +3, dan +1
+3, +3, dan +2
+3, +6, dan +5
+2, -2, dan +5
+2,+6, dan +2
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Dalam penyetaraan reaksi redoks Cr2O72- + Fe2++ H+ → Cr3++ Fe3++ H2O, jumlah koefisien H2O dan H+ adalah….
7H2O dan 14H+
8H2O dan 16H+
7H2O dan 8H+
8H2O dan 14H+
6H2O dan 12H+
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Reaksi lengkap untuk setengah reaksi berikut NO3-→NO dalam suasana asam adalah….
NO3- + 4H+ + 3e →NO + 4H2O
NO3- + 8H+ + 7e →NO + 4H2O
2NO3- + 4H+ + 3e →2NO + 4H2O
NO3- + 4H+ + 3e →NO + 2H2O
NO3- + 7H+ + 6e →NO + 7H2O
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