You have two test tubes. One test tube contains Pb +2 (aq) solution and the other test tube contains Bi +3 (aq). Predict what will happen when HCl (aq) is added to both test tubes. If a reaction occurs, what is the new chemical fomula?

Pb +2 (aq) will form a white precipitate, PbCl 2 (s). Bi +3 (aq) will remain unchanged.

Pb +2 (aq) will remain unchanged. Bi +3 (aq) will form a white precipitate, Bi(OH) 3 (s).

Pb +2 (aq) will form a yellow precipitate, PbCrO 4 (s). Bi +3 (aq) will remain unchanged.

Pb +2 (aq) will remain unchanged. Bi +3 (aq) will form a white precipitate, Bi (s).

You have two test tubes. One test tube contains Pb +2 (aq) solution and the other test tube contains Bi +3 (aq). Predit what will happen when HCl (aq) is added to both test tubes. If a reaction occurs, what is the new chemical fomula?

Pb +2 (aq) will form a white precipitate, PbCl 2 (s). Bi +3 (aq) will remain unchanged.

Pb +2 (aq) will remain unchanged. Bi +3 (aq) will form a white precipitate, Bi(OH) 3 (s).

Pb +2 (aq) will form a yellow precipitate, PbCrO 4 (s). Bi +3 (aq) will remain unchanged.

Pb +2 (aq) will remain unchanged. Bi +3 (aq) will form a white precipitate, Bi (s).

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment. In step 1-D, after the 6 M NH 3 was added, the white precipitate dissolved creating a colorless solution. Then, after the addition of 6 M HNO 3 (and the solution tested acidic), a white precipitate formed.

Ag+ and Pb+2 are indicated as possibly present

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment. In step 1-C, after adding the CH 3 COOH and K 2 CrO 4 , the colorless solution turned yellow and no solid formed.

Ag+ and Pb+2 are indicated as possibly present

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment. In step 1-A after adding the 6 M HCl to an unknown, a white precipitate formed with a colorless decantate.

Ag+ and Pb+2 are indicated as possibly present

Select the step(s) that will compose a rationale for the cation Bi +3 being absent in an unknown.

A white precipitate did not form in step 2-B.

The presence of a light blue decantate in step 1-A.

yellow precipitate did not form when K 2 CrO 4 was added in step 1-C.

All of the white precipitate from step 1-A dissolved in hot water.

Select the step(s) that will compose a rationale for the cation Cu +2 being present in an unknown.

The formation of a dark blue solution in step 2-B.

A reddish brown precipitate formed after adding K 4 Fe(CN) 6 in step 2-E.

Dark blue solution turned to light blue in step 2-D after the addition of CH 3 COOH and then

A white precipitate formed when 6 M HCl was added to the unknown solution in step 1-A.

The white precipitate from step 1-B dissolved in 6 M NH 3 and then reformed when 6 M HNO 3 was added.

You have two test tubes. One test tube contains Mn +2 (aq) solution and the other test tube contains Zn +2 (aq). Predict what will happen when NaOH(aq) is added to both test tubes. If a reaction occurs, what is the new chemical formula?

Mn +2 (aq) will form a very pale pink precipitate, Mn(OH) 2 (s). Zn +2 (aq) will form a colorless solution, [Zn(OH) 4 ] -2 (aq).

Mn +2 (aq) will form a very pale pink precipitate, Mn(OH) 2 (s). Zn +2 (aq) will form a white precipitate, Zn(OH) 2 (s).

Mn +2 (aq) will will remain unchanged, a nearly colorless solution. Zn +2 (aq) will form a green solution, [Zn(OH) 4 ] -2 (aq).

Mn +2 (aq) will form a purple solution, MnO 4 - (aq). Zn +2 (aq) will form a grey-white solid, ZnK 2 Fe(CN) 6 (s).

You have two test tubes. One test tube contains Cr +3 (aq) solution and the other test tube contains Ni +2 (aq). Predict what will happen when NaOH(aq) is added to both test tubes. If a reaction occurs, what is the new chemical formula?

Cr +3 (aq) will form a green solution, [Cr(OH) 4 ] - (aq). Ni +2 (aq) will form a green precipitate,Ni(OH) 2 (s).

Cr +3 (aq) will form a green solution, [Cr(OH) 4 ] - (aq). Ni +2 (aq) will remain the same, a green solution.

Cr +3 (aq) will remain unchanged, an indigo blue solution. Ni +2 (aq) will form a green solid, Ni(OH) 2 (s).

Cr +3 (aq) will form a yellow-tan solid, BaCrO 4 (s). Ni +2 (aq) will form a red-pink solid, Ni(HDMG) 2 (s).

In step 3-A, when NaOH was added to the original solution, a precipitate formed.

At least one of Fe+3, Ni+2, and Mn+2 is indicated as present.

In step 3-G after adding the NaBiO 3 and centrifuging, a brown solution formed over the excess mustard colored NaBiO 3

At least one of Fe+3, Ni+2, and Mn+2 is indicated as present.

In Step 3-H after the addition of BaCl 2 , the solution remained the same.

At least one of Fe+3, Ni+2, and Mn+2 is indicated as present.

When the H 2 DMG was added in step 3-F, a strawberry red precipitate formed.

At least one of Fe+3, Ni+2, and Mn+2 is indicated as present.

Select the steps that will compose a rationale for the cation Cr +3 being absent in an unknown.

The lack of a yellow solution after the addition of H 2 O 2 in step 3-B.

After the BaCl 2 was added in step 3-H, a colorless solution with no solid was present.

The lack of a green decanate after the addition of excess NaOH in step 3-A.

A precipitate did not form when 6 M NaOH was added to the unknown solution in step 3-A.

Select the step(s) that will compose a rationale for the cation Zn +2 being present in an unknown.

The colorless decantate was isolated in step 3-H when BaCl 2 was added.

A grey-white solid formed in step 3-J.

A purple-grape supernate over excess NaBiO 3 formed in 3-G.

A pale yellow (tan) precipitate formed in step 3-H.

In a certain reaction, a solid chemical dissolved in water. The temperature of the water sample rose from 22.4°C to 27.3°C. Select all the statements that are true about this experiment.

The water is defined as the surroundings.

The water is defined as the system.

If an error caused the initial temperature to be larger (and the final temperature okay), how does this affect the calculation of the heat of solution (q solution )?

The larger T initial would produce a smaller ΔT, which would result in a smaller q.

The larger T initial would produce a larger ΔT, which would result in a smaller q.

The larger T initial would produce a larger ΔT, which would result in a larger q.

The larger T initial would produce a smaller ΔT, which would result in a larger q.

For the following error, select the answer that correctly describes how it will affect the value of the final temperature of the water/solution in the calorimeter: Some of the HCl solution was spilled on the lab bench and not successfully added to the calorimeter.

Decreases the value of final Temperature

Increases the value of final Temperature

Consider the benzoic acid dissociation reaction below which is at equilibrium. C 6 H 5 COOH(aq) + H 2 O(ℓ) ⇋ C 6 H 5 COO - (aq) + H 3 O + (aq) If additional C 6 H 5 COOH, benzoic acid, is added to the system (stress), how will the system change in order to re-establish equilibrium? Select all that might apply.

The concentration of C 6 H 5 COO - will increase.

The concentration of C 6 H 5 COOH will decrease.

The concentration of H 3 O + will decrease.

The concentration of C 6 H 5 COOH will increase.

[Cu(H 2 O) 4 ] +2 (or simply as Cu +2 ) is a sky blue solution and [Cu(NH 3 ) 4 ] +2 is a dark royal blue solution. [Cu(H 2 O) 4 ] +2 (aq) + 4 NH 3 (aq) ⇋ [Cu(NH 3 ) 4 ] +2 (aq) + 4 H 2 O(ℓ) Make a hypothesis on what will occur in the equilibrium system (initially a medium blue solution) if HCl is added. Then explain what will occur in terms of Le Châtelier’s principle.

The solution will become a lighter blue solution. The system must shift towards reactants since acid removes the NH 3 , the system shifts to replace the NH 3 .

The solution will become a darker blue solution. The system must shift towards products to offset the acid by producing more [Cu(NH 3 ) 4 ] +2 (aq).

The solution will become a darker blue solution. The system must shift towards reactants since the acid forces the [Cu(NH 3 ) 4 ] +2 (aq) to dissociate.

The solution will remain the same color. The system will re-establish the equilibrium since the HCl and NH 3 cancel each other.

Predict the equilibrium shifts that will occur in the endothermic equilibrium reaction below in order to re-establish equilibrium. Increasing the overall pressure of the equilibrium system. CH 4 (g) + H 2 O(g) ⇋ CO(g) + 3 H 2 (g)

Will shift the equilibrium towards the reactants.

Will shift the equilibrium towards the products.

Predict the equilibrium shifts that will occur in the endothermic equilibrium reaction below in order to re-establish equilibrium. Increasing the overall temperature of the equilibrium system. CH 4 (g) + H 2 O(g) ⇋ CO(g) + 3 H 2 (g)

Will shift the equilibrium towards the products.

Will shift the equilibrium towards the reactants.

Predict the equilibrium shifts that will occur in the endothermic equilibrium reaction below in order to re-establish equilibrium. Decreasing the overall total pressure of the equilibrium system. CH 4 (g) + H 2 O(g) ⇋ CO(g) + 3 H 2 (g)

Will shift the equilibrium towards the products.

Will shift the equilibrium towards the reactants.

Predict the equilibrium shifts that will occur in the endothermic equilibrium reaction below in order to re-establish equilibrium. Increasing the partial pressure of steam. CH 4 (g) + H 2 O(g) ⇋ CO(g) + 3 H 2 (g)

Will shift the equilibrium towards the products.

Will shift the equilibrium towards the reactants.

Chemistry Lab Final Part 2

Authored by Norm Brown

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FILL IN THE BLANKS QUESTION

1 min • 1 pt

To carefully pour a liquid into another container.

(a)

FILL IN THE BLANKS QUESTION

1 min • 1 pt

The liquid that was carefully poured into a new container.

(a)

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

CH₃COOH and HC₂H₃O₂ are different ways of writing the chemical formula of the which chemical ?

acetic acid

acetate ion

peracetic acid

acetone

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the chemicals are oxidants?

HCl

HNO₃

K₂CrO₄

NH3

SnCl₂

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

You have two test tubes. One test tube contains Pb⁺²(aq) solution and the other test tube contains Bi⁺³(aq).
Predict what will happen when HCl (aq) is added to both test tubes.
If a reaction occurs, what is the new chemical fomula?

Pb⁺²(aq) will remain unchanged.
Bi⁺³(aq) will form a white precipitate, Bi(OH)₃ (s).

Pb⁺²(aq) will form a white precipitate, PbCl₂ (s).
Bi⁺³(aq) will remain unchanged.

Pb⁺²(aq) will form a yellow precipitate, PbCrO₄(s).
Bi⁺³(aq) will remain unchanged.

Pb⁺²(aq) will remain unchanged.
Bi⁺³(aq) will form a white precipitate, Bi (s).

You have one test tube which contains a colorless solution that is either Cu⁺² (aq) or Bi⁺³(aq).
Select a reagent that will allow you to differentiate between the two chemical species.
If the solution is Cu⁺², what will happen when the reagent is added?
If the solution is Bi⁺³, what will happen when the reagent is added?
Select one:

15 M NH₃
If it is Cu⁺², a dark blue solution will form after adding the 15 M NH₃.
If it is Bi⁺³, a white precipitate will form after adding the 15 M NH₃.

HCl
If it is Cu⁺², a white precipitate will form after adding the HCl.
If it is Bi⁺³, the solution will remain the same after adding the HCl.

NaOH + SnCl₂

If it is Cu⁺², a black solid will form after adding the NaOH + SnCl₂.
If it is Bi⁺³, a white solid will form after adding the NaOH + SnCl₂.

HCl

If it is Cu⁺², the solution will remain the same after adding the HCl.
If it is Bi⁺³, a white precipitate will form after adding the HCl.

You have two test tubes. One test tube contains Pb⁺²(aq) solution and the other test tube contains Bi⁺³(aq).
Predit what will happen when HCl (aq) is added to both test tubes.
If a reaction occurs, what is the new chemical fomula?

Pb⁺²(aq) will remain unchanged.
Bi⁺³(aq) will form a white precipitate, Bi(OH)₃ (s).

Pb⁺²(aq) will form a white precipitate, PbCl₂ (s).
Bi⁺³(aq) will remain unchanged.

Pb⁺²(aq) will form a yellow precipitate, PbCrO₄(s).
Bi⁺³(aq) will remain unchanged.

Pb⁺²(aq) will remain unchanged.
Bi⁺³(aq) will form a white precipitate, Bi (s).

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Chemistry Lab Final Part 2

To carefully pour a liquid into another container. (a)

The liquid that was carefully poured into a new container. (a)

CH3COOH and HC2H3O2 are different ways of writing the chemical formula of the which chemical ?

Which of the chemicals are oxidants?

You have two test tubes. One test tube contains Pb+2 (aq) solution and the other test tube contains Bi+3(aq).Predict what will happen when HCl (aq) is added to both test tubes.If a reaction occurs, what is the new chemical fomula?

You have two test tubes. One test tube contains Pb+2 (aq) solution and the other test tube contains Bi+3(aq).Predit what will happen when HCl (aq) is added to both test tubes.If a reaction occurs, what is the new chemical fomula?

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment.In step 1-C, after adding the CH3COOH and K2CrO4, the colorless solution turned yellow and no solid formed.

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment.In step 1-A after adding the 6 M HCl to an unknown, a white precipitate formed with a colorless decantate.

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To carefully pour a liquid into another container.

(a)

The liquid that was carefully poured into a new container.

(a)

CH₃COOH and HC₂H₃O₂ are different ways of writing the chemical formula of the which chemical ?

You have two test tubes. One test tube contains Pb⁺²(aq) solution and the other test tube contains Bi⁺³(aq).
Predict what will happen when HCl (aq) is added to both test tubes.
If a reaction occurs, what is the new chemical fomula?

You have two test tubes. One test tube contains Pb⁺²(aq) solution and the other test tube contains Bi⁺³(aq).
Predit what will happen when HCl (aq) is added to both test tubes.
If a reaction occurs, what is the new chemical fomula?

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment.
In step 1-C, after adding the CH₃COOH and K₂CrO₄, the colorless solution turned yellow and no solid formed.

Match the correct inference to the description of the reactions from the Group 1 & 2 Qualitative Analysis Experiment.
In step 1-A after adding the 6 M HCl to an unknown, a white precipitate formed with a colorless decantate.