Algebra 2 Unit 4B Review OL

The quadratic equation k2 - 12k = -11 has two potential solutions. Use the X-method to factor the quadratic and find these two solutions.

• k = 11

  k = 1

• k = -11

  k = -1

• k = 11

  k = -1

• k = -11

  k = 1

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.

4x² + 2x = 12

• 3(x - 4)(x + 1)

• 4(x + 2)(x - 3)

• 2(2x - 3)(x+2)

• (2x - 6)(x + 2)

Tags

CCSS.HSA-REI.B.4B

Solve the following quadratic using factoring.

x² = 81

• x = 9

• x = 0

• x = 9i

• x = 9 and

  x = -9

• There are no solutions

Tags

CCSS.HSA-REI.B.4B

Solve using the quadratic formula. 

2m² – 7m – 13 = -10  

Tags

CCSS.HSA-REI.B.4B

Solve using the quadratic formula.       

 a² – 7 = -2a

Tags

CCSS.HSA-REI.B.4B

Mackenzie claims that the equation

 y = x² + 8x - 33 does not have any real solutions.  Is she correct?

• No, Mackenzie is not correct; the equation has real solutions.
• Yes, Mackenzie is correct; the equation has no real solutions.

Tags

CCSS.HSA-REI.B.4B

Find the number and type of roots of each example below. All of the following have exactly two roots EXCEPT:

• f(x) = (⅕)x² + 7x - 15

• f(x) = (-⅓)x² + 9x + 18

• f(x) = 3x² - 8x + 3

• f(x) = x² - 14x + 49

Tags

CCSS.HSA-REI.B.4B

Solve the equation 5h² + 3h + 3 = 0.

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

Simplify.

(-2 - 5i) - (-8 + 8i)

• -6 + 3i
• 4 + 5i
• 6 - 13i
• -10 - 3i

Tags

CCSS.HSN.CN.A.2

Simplify.

(8 - 4i)(2 - 6i)

• -8 + 32i
• -8 - 56i

• 16 - 24i
• -16 + 12i

Tags

CCSS.HSN.CN.A.2