Mod 3 Topic 2 Test Corrections

Mod 3 Topic 2 Test Corrections

7th Grade

11 Qs

quiz-placeholder

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Mod 3 Topic 2 Test Corrections

Mod 3 Topic 2 Test Corrections

Assessment

Quiz

Mathematics

7th Grade

Medium

TEKS
MATH.7.3A, MATH.7.7A, MATH.7.3B

Standards-aligned

Created by

Travis Robertson

Used 2+ times

FREE Resource

11 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To combine like terms, group the x terms and the constant terms: (4x - 2x) + (9 + 3) = 2x + 12. Thus, the correct answer is 2x + 12.

Tags

TEKS.MATH.7.3A

TEKS.MATH.7.3B

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To find the total cost, substitute x = 6 into the cost formula: 3(6) + 5 = 18 + 5 = 23. Thus, Mia spends a total of 23 dollars.

Tags

TEKS.MATH.7.3A

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

Distributing gives 6(3x) + 6(2) - 4x = 18x + 12 - 4x. Combining like terms, 18x - 4x = 14x, so the final result is 14x + 12, which matches the correct answer.

Tags

TEKS.MATH.7.3A

TEKS.MATH.7.3B

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Answer explanation

To combine like terms, subtract the coefficients of y: 9y - 3y = 6y. Then, combine the constants: 4 - 2 = 2. Thus, the result is 6y + 2, which matches the correct answer.

Tags

TEKS.MATH.7.3A

TEKS.MATH.7.3B

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

8

Answer explanation

Substituting x = 3 and y = 2 into the expression 4x - 3y + 2 gives 4(3) - 3(2) + 2 = 12 - 6 + 2 = 8. Therefore, the correct evaluation is 11.

Tags

TEKS.MATH.7.3A

TEKS.MATH.7.3B

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Distribute:

5(3y-2+4x)

**PAY ATTENTION TO THE SIGNS**

15y-10+4x

25yx

15y-10+20x

15y+10+20x

Answer explanation

To distribute 5(3y - 2 + 4x), multiply each term inside the parentheses by 5: 5*3y = 15y, 5*(-2) = -10, and 5*4x = 20x. Combining these gives 15y - 10 + 20x, which matches the correct answer.

Tags

TEKS.MATH.7.3A

7.

MATCH QUESTION

1 min • 1 pt

Match the following expressions with what it would be AFTER you distribute.

6(x -3)

6x +18

-6 (x +3)

-6x -18

-6(x -3)

-6x +18

6(x +3)

6x -18

Tags

TEKS.MATH.7.3A

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