PHYSICS 1 CYCLE 3 - End of Cycle Assessment

Doubling the distance between two charges will result in the force:

• A) Being halved.

• B) Being doubled.

• C) Being quartered.

• D) Remaining the same.

Answer explanation

According to Coulomb's law, the force between two charges is inversely proportional to the square of the distance between them. Doubling the distance results in the force being reduced to one-fourth, or quartered.

Tags

NGSS.HS-PS2-4

What type of force is described by Coulomb's Law?

• A) Gravitational Force

• B) Electromagnetic Force

• C) Nuclear Force

• D) Frictional Force

Answer explanation

Coulomb's Law describes the force between charged particles, which is a fundamental aspect of the electromagnetic force. It quantifies the attraction or repulsion between two charges, making B) Electromagnetic Force the correct choice.

Tags

NGSS.HS-PS2-4

Two charges, q1​=2μC and q2​=3μC, are separated by a distance of 0.5 m. What is the magnitude of the force between them? (Use k=9×10^ 9 Nm^2/C^2)

• A. 216 N

• B. 2.7 N

• C. 108 N

• D. 324 N

Answer explanation

Using Coulomb's law, F = k * |q1 * q2| / r^2. Substituting values: F = (9×10^9) * (2×10^-6 * 3×10^-6) / (0.5^2) = 216 N. Thus, the correct answer is A. 216 N.

Tags

NGSS.HS-PS2-4

NGSS.HS-PS3-5

Two charges exert a force of 10N on each other. If one charge is doubled while the distance remains constant, what is the new force?

• A) 20 N

• B) 40 N

• C) 5 N

• D) 10 N

Answer explanation

According to Coulomb's law, the force between two charges is directly proportional to the product of the charges. Doubling one charge while keeping the distance constant doubles the force from 10 N to 20 N. Thus, the new force is 20 N.

Tags

NGSS.HS-PS2-4

NGSS.HS-PS3-5

Coulomb’s Law states that the force between two charges is proportional to:

• A) The square of the distance.

• B) The product of the charges.

• C) The sum of the charges.

• D) The distance between them.

Answer explanation

Coulomb’s Law states that the force between two charges is proportional to the product of the charges (Choice B). This means that as either charge increases, the force between them also increases.

Tags

NGSS.HS-PS2-4

The force between two charges decreases as the magnitude of one charge decreases.

• True

• False

Answer explanation

True. According to Coulomb's law, the force between two charges is directly proportional to the product of their magnitudes. Thus, if the magnitude of one charge decreases, the overall force also decreases.

Tags

NGSS.HS-PS2-4

Coulomb’s Law applies to both attractive and repulsive forces between two charges.

• True

• False

Answer explanation

True. Coulomb’s Law describes the force between two charges, which can be either attractive (opposite charges) or repulsive (like charges), thus applying to both types of forces.

Tags

NGSS.HS-PS2-4

A test charge q=2μC experiences a force of 6N in an electric field. What is the magnitude of the electric field? Formula: E=F/q

• A) 3 N/C

• B) 3000 N

• C) 12 N/C

• D) 6000 N/C

Answer explanation

To find the electric field E, use the formula E = F/q. Here, F = 6N and q = 2μC = 2 x 10^-6 C. Thus, E = 6N / (2 x 10^-6 C) = 3 x 10^6 N/C = 12 N/C. Therefore, the correct answer is C) 12 N/C.

Tags

NGSS.HS-PS2-4

What is the electric field produced by a point charge of 5μC at a distance of 0.2m? (Use k=9×10^9 N.m^2/C^2) Formula: E=fq/r^2

• A) 1.125 x 10^6 N/C

• B) 2.125 x 10^6 N/C

• C) 2.25 x 10^6 N/C

• D) 5.0 x 10^6 N/C

Answer explanation

Using the formula E = k * |q| / r^2, we substitute k = 9×10^9 N.m^2/C^2, q = 5μC (5×10^-6 C), and r = 0.2m. This gives E = (9×10^9) * (5×10^-6) / (0.2)^2 = 1.125 x 10^6 N/C, which corresponds to choice A.

Tags

NGSS.HS-PS2-4

What is the direction of the electric field produced by a positive charge?

• A) Toward the charge

• B) Away from the charge

• C) Perpendicular to the charge

• D) No electric field is produced

Answer explanation

The electric field produced by a positive charge points away from the charge. This is because positive charges repel other positive charges, creating a field that radiates outward.