Flashcard No. 7.1-7.2 in Geometry (Trigonometric Ratios )
Flashcard
•
Mathematics
•
9th Grade
•
Hard
+1
Standards-aligned
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1.
FLASHCARD QUESTION
Front
What is the Tangent Ratio in a right triangle?
Back
The Tangent Ratio is defined as the ratio of the length of the opposite side to the length of the adjacent side. It is expressed as: \( \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \)
Tags
CCSS.HSG.SRT.C.6
2.
FLASHCARD QUESTION
Front
What is the Sine Ratio in a right triangle?
Back
The Sine Ratio is defined as the ratio of the length of the opposite side to the length of the hypotenuse. It is expressed as: \( \sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} \)
Tags
CCSS.HSG.SRT.C.6
3.
FLASHCARD QUESTION
Front
What is the Cosine Ratio in a right triangle?
Back
The Cosine Ratio is defined as the ratio of the length of the adjacent side to the length of the hypotenuse. It is expressed as: \( \cos(\theta) = \frac{\text{adjacent}}{\text{hypotenuse}} \)
Tags
CCSS.HSG.SRT.C.6
4.
FLASHCARD QUESTION
Front
How do you determine which trigonometric ratio to use?
Back
To determine which trigonometric ratio to use, identify the sides of the triangle you know and the side you need to find. Use Tangent if you have opposite and adjacent, Sine if you have opposite and hypotenuse, and Cosine if you have adjacent and hypotenuse.
Tags
CCSS.HSG.SRT.C.6
5.
FLASHCARD QUESTION
Front
What is the formula to find the angle using the Tangent Ratio?
Back
To find the angle using the Tangent Ratio, use the inverse tangent function: \( \theta = \tan^{-1}\left(\frac{\text{opposite}}{\text{adjacent}}\right) \)
Tags
CCSS.HSG.SRT.C.8
6.
FLASHCARD QUESTION
Front
If the opposite side is 3 and the adjacent side is 4, what is the Tangent Ratio?
Back
The Tangent Ratio is \( \tan(\theta) = \frac{3}{4} = 0.75 \)
Tags
CCSS.HSG.SRT.C.6
7.
FLASHCARD QUESTION
Front
What is the relationship between the three trigonometric ratios?
Back
The three trigonometric ratios (Sine, Cosine, Tangent) are related through the Pythagorean identity: \( \sin^2(\theta) + \cos^2(\theta) = 1 \) and \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \)
Tags
CCSS.HSG.SRT.C.7
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