Irregularly Shaped Conductors in Electrostatic Equilibrium

What happens to the local surface charge density when the radius of curvature is at its minimum?

• It decreases.

• It reaches its maximum.

• It becomes zero.

• It remains constant.

In the example of two conducting spheres, what is the primary reason for charge redistribution?

• To equalize the mass of the spheres.

• To ensure both spheres have the same electric potential.

• To minimize the distance between the spheres.

• To maximize the charge on the larger sphere.

How quickly does the charge redistribution occur when two conductors touch?

• It takes a few hours.

• It happens almost instantaneously.

• It takes several minutes.

• It never completes.

What is the relationship between the electric field and the radius of curvature on the surface of a conductor?

• The electric field is stronger where the radius of curvature is smaller.

• The electric field is weaker where the radius of curvature is smaller.

• The electric field is independent of the radius of curvature.

• The electric field is the same regardless of the radius of curvature.

What does the electric field at the surface of a conductor in electrostatic equilibrium equal?

• The local surface charge density divided by permittivity of free space.

• The local surface charge density minus permittivity of free space.

• The local surface charge density multiplied by permittivity of free space.

• The local surface charge density plus permittivity of free space.