(part 2 of 2) An Introductory Projectile Motion Problem with an Initial Horizontal Velocity

What is the initial condition of the projectile's velocity in the y-direction?

• It is equal to the initial velocity in the x-direction.

• It is zero.

• It is equal to the final velocity in the y-direction.

• It is equal to the acceleration due to gravity.

Why is the final velocity in the y-direction negative?

• Because the ball is moving upwards.

• Because the ball is moving downwards.

• Because the initial velocity is negative.

• Because the acceleration is positive.

What is the constant velocity of the ball in the x-direction?

• 4.47 meters per second

• 3.7 meters per second

• 5.8 meters per second

• 9.81 meters per second

How do you calculate the resultant velocity of the projectile?

• By adding the velocities in the x and y directions.

• By multiplying the velocities in the x and y directions.

• By subtracting the velocity in the y-direction from the x-direction.

• By using the Pythagorean theorem on the x and y components.

What is the angle of the final velocity vector relative to the negative y-axis?

• 60 degrees

• 50 degrees

• 45 degrees

• 30 degrees

Why does the ball appear to move straight down from the perspective of the hand?

• Because both the hand and the ball have the same horizontal velocity.

• Because the ball has no horizontal motion.

• Because the hand moves faster than the ball.

• Because the ball is stationary.

How does the motion of the ball differ from the motion of the hand?

• The ball moves only in the x-direction.

• The ball moves in both x and y directions, while the hand moves only in the x-direction.

• The hand moves in both x and y directions, while the ball moves only in the x-direction.

• Both move in the same direction and distance.