Search Header Logo
Understand where the pythagorean identities come from

Understand where the pythagorean identities come from

Assessment

Interactive Video

Mathematics

11th Grade - University

Practice Problem

Hard

Created by

Wayground Content

FREE Resource

The video tutorial explores the relationship between right triangles and trigonometry, focusing on the Pythagorean theorem and its application within the unit circle. It explains the correct notation for squaring trigonometric functions and derives Pythagorean identities for various trigonometric functions, emphasizing the importance of understanding function squaring versus angle squaring.

Read more

7 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary relationship discussed in the context of right triangles?

The relationship between tangent and secant

The relationship between angles and sides

The Pythagorean theorem

The relationship between sine and cosine

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the Pythagorean identity typically expressed using trigonometric functions?

sin²(θ) - cos²(θ) = 1

tan²(θ) + sec²(θ) = 1

cos(θ) + sin(θ) = 1

cos²(θ) + sin²(θ) = 1

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the correct way to write the square of cosine of an angle?

cos(θ) * cos(θ)

cos(θ)²

cos²(θ)

cos(θ) + cos(θ)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens if you square the angle instead of the trigonometric function?

You get the same result

You square the function

You solve a different problem

You get a negative result

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of dividing sine squared by cosine squared?

Tangent squared

Secant squared

Cotangent squared

Cosecant squared

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric function is the reciprocal of cosine?

Sine

Tangent

Secant

Cosecant

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the Pythagorean identity involving cotangent and cosecant?

cot²(θ) + csc²(θ) = 2

cot²(θ) + csc²(θ) = 0

cot²(θ) + csc²(θ) = 1

cot²(θ) - csc²(θ) = 1

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Classlink

Continue with Classlink

Clever

Continue with Clever

or continue with

Microsoft

Microsoft

Apple

Apple

Others

Others

Already have an account?