Логарифм и функция Quiz: 23 Practice Questions (Grade 10)

23 questions

Show all answers

1.

MULTIPLE SELECT QUESTION

2 mins • 2 pts

Условиями существования логарифма числа b по основанию a являются

a>0

$a\ne1$

b>0

a<0

Answer explanation

https://skysmart.ru/articles/mathematic/logarifmy

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Логарифм числа 8 по основанию 2

$\log_28$

$\log_82$

$\log_2^8$

$\log2^8$

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Логарифм числа 9 по основанию 17

$\log_{17}9$

$\log_917$

$\log_9^{17}$

$\log17^9$

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Логарифм по основанию 6 от 216

$\log_{216}6$

$\log_6216$

$\log_6^{216}$

$\log216$

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Логарифм по основанию одна третья от девяти

$\log_93$

$\log_31$

$\log_{\frac{1}{3}}^{ }9$

$\log_9\frac{1}{3}$

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Восстановите основное логарифмическое тождество: $a^{\log_ab}=$

a

b

$\log_ab$

$a^b$

7.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

$\log_a1=$

(a)

8.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

$\log_aa=$

(a)

9.

FILL IN THE BLANKS QUESTION

1 min • 1 pt

$\log_{11}121=$

(a)

10.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Найдите логарифм по основанию 3 числа $\frac{1}{27}$

3

9

-3

-9

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Логарифм и функция

Условиями существования логарифма числа b по основанию a являются

https://skysmart.ru/articles/mathematic/logarifmy

Логарифм числа 8 по основанию 2

Логарифм числа 9 по основанию 17

Логарифм по основанию 6 от 216

Логарифм по основанию одна третья от девяти

Восстановите основное логарифмическое тождество: alog⁡ab=a^{\log_ab}=aloga​b=

log⁡a1=\log_a1=loga​1= (a)

log⁡aa=\log_aa=loga​a= (a)

log⁡11121=\log_{11}121=log11​121= (a)

Найдите логарифм по основанию 3 числа 127\frac{1}{27}271​

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Discover more resources for Mathematics

Восстановите основное логарифмическое тождество: $a^{\log_ab}=$

$\log_a1=$

(a)

$\log_aa=$

(a)

$\log_{11}121=$

(a)

Найдите логарифм по основанию 3 числа $\frac{1}{27}$