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Act 1-10 Complex Numbers Practice

Authored by Behzad Shirazifard

Mathematics

11th Grade

CCSS covered

Used 3+ times

Act 1-10 Complex Numbers Practice
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10 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

Simplify (3+4i)+(2−5i)

5 - i

6 + i

1 + 3i

-1 + 2i

Answer explanation

To simplify (3+4i)+(2−5i), combine the real parts: 3 + 2 = 5, and the imaginary parts: 4i - 5i = -i. Thus, the result is 5 - i, which matches the correct answer.

Tags

CCSS.HSN.CN.A.2

2.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

Simplify (2+3i)−(5+i)

2 + 4i

-3 + 2i

-1 + 3i

0 + 2i

Answer explanation

To simplify (2+3i)−(5+i), subtract the real and imaginary parts: (2-5) + (3-1)i = -3 + 2i. Thus, the correct answer is -3 + 2i.

Tags

CCSS.HSN.CN.A.2

3.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

Multiply (1+2i)(3−i)

1 + 5i

4 - i

3 + 2i

2 + 6i

Answer explanation

To multiply (1+2i)(3−i), use the distributive property: 1*3 + 1*(-i) + 2i*3 + 2i*(-i) = 3 - i + 6i + 2 = 5i + 1. Thus, the correct answer is 1 + 5i.

Tags

CCSS.HSN.CN.A.2

4.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

What is the conjugate of 4+6i

4+6i

4-6i

-4+6i

4-6i+2

Answer explanation

The conjugate of a complex number is obtained by changing the sign of the imaginary part. For 4+6i, the conjugate is 4-6i, which is the correct choice among the options provided.

Tags

CCSS.HSN.CN.A.3

5.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

1+2i

1-2i

2+i

2-i

1-i

Answer explanation

To simplify \( \frac{2}{1+i} \), multiply the numerator and denominator by the conjugate \( 1-i \): \( \frac{2(1-i)}{(1+i)(1-i)} = \frac{2-2i}{1^2 - i^2} = \frac{2-2i}{2} = 1-i \). Thus, the correct answer is \( 1-i \).

Tags

CCSS.HSN.CN.A.3

6.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

1

-i

i

-1

Answer explanation

To solve i^{2023}, we note that i cycles every 4 powers: i, -1, -i, 1. Since 2023 mod 4 equals 3, i^{2023} = i^3 = -i. Thus, the correct answer is -i.

Tags

CCSS.HSN.CN.A.2

7.

MULTIPLE CHOICE QUESTION

15 mins • 10 pts

5

7

3+4i

1

Answer explanation

To find the magnitude of z = 2 - i, use |z| = √(a² + b²), where a = 2 and b = -1. Thus, |z| = √(2² + (-1)²) = √(4 + 1) = √5. Therefore, the correct answer is √5.

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