Exponential Growth & Decay

Exponential Growth & Decay

Assessment

Flashcard

Mathematics

8th - 10th Grade

Hard

CCSS
HSF-IF.C.8B, HSF.LE.B.5, HSF-LE.A.1A

Standards-aligned

Created by

Quizizz Content

FREE Resource

Student preview

quiz-placeholder

15 questions

Show all answers

1.

FLASHCARD QUESTION

Front

What is exponential growth?

Back

Exponential growth occurs when the increase of a quantity is proportional to its current value, leading to growth at an increasing rate over time.

Tags

CCSS.HSF-LE.A.1A

2.

FLASHCARD QUESTION

Front

What is exponential decay?

Back

Exponential decay describes a decrease in quantity where the rate of decrease is proportional to the current amount, resulting in a rapid decline that slows over time.

Tags

CCSS.HSF-IF.C.8B

3.

FLASHCARD QUESTION

Front

What does the variable 'a' represent in the function f(x) = a(b)^x?

Back

The variable 'a' represents the initial amount or starting value in the exponential function.

Tags

CCSS.HSF.LE.B.5

4.

FLASHCARD QUESTION

Front

What does the variable 'b' represent in the function f(x) = a(b)^x?

Back

The variable 'b' is the base of the exponential function, representing the growth (b > 1) or decay (0 < b < 1) factor.

Tags

CCSS.HSF-IF.C.8B

5.

FLASHCARD QUESTION

Front

How do you identify exponential growth from a function?

Back

Exponential growth can be identified if the base 'b' in the function f(x) = a(b)^x is greater than 1.

Tags

CCSS.HSF-IF.C.8B

6.

FLASHCARD QUESTION

Front

How do you identify exponential decay from a function?

Back

Exponential decay can be identified if the base 'b' in the function f(x) = a(b)^x is between 0 and 1.

Tags

CCSS.HSF-IF.C.8B

7.

FLASHCARD QUESTION

Front

What is the common ratio in the function f(x) = 300(1.16)^x?

Back

The common ratio is 1.16, indicating a 16% increase for each unit increase in x.

Create a free account and access millions of resources

Create resources
Host any resource
Get auto-graded reports
or continue with
Microsoft
Apple
Others
By signing up, you agree to our Terms of Service & Privacy Policy
Already have an account?