George has 45 toy cars. This is 5 times as many toy cars as Martha has. How many toy cars does Martha have?

Which equation represents how to find the value of n?

• 6 x n = 45

• 5 x n = 45

• 45 = 5 + n

• 45 x 5 = n

Answer explanation

George has 45 toy cars, which is 5 times as many as Martha. To find how many cars Martha has, we can set up the equation 5 x n = 45, where n represents the number of cars Martha has.

Tags

CCSS.4.OA.A.1

Arturo has 63 basketball cards. His brother Saul has 9 cards. How many times as many cards does Arturo have than Saul?

Choose an equation that can be used to solve this problem.

• 9 x 63 = 567

• 63 - 9 = 54

• 9 + 63 = 72

• 63 ÷ 9 = 7

Answer explanation

To find how many times as many cards Arturo has compared to Saul, we divide the number of Arturo's cards (63) by the number of Saul's cards (9). The equation 63 ÷ 9 = 7 shows that Arturo has 7 times as many cards.

Tags

CCSS.4.OA.A.1

Which equation matches the bar model?

• 21 = 3 x 7

• 21 = 4 x 7

• 21 = 4 + 7

• 21 = 3 + 7

Answer explanation

The bar model represents 3 groups of 7, which corresponds to the equation 21 = 3 x 7. This shows that 3 multiplied by 7 equals 21, matching the model accurately.

Tags

CCSS.2.OA.C.4

Which equation could be modeled using this diagram?

• 8 + 4 = 12

• 8 - 3 = 5

• 3 x 8 = 24

• 4 x 8 = 32

Answer explanation

The diagram likely represents groups of 3, with 8 groups total, leading to the equation 3 x 8 = 24. This matches the correct choice, as it illustrates multiplication of groups, unlike the other options.

Tags

CCSS.2.OA.C.4

Jamillia drew a bar model for the equation 18 = 3 x 6. Which number should she put inside the blocks?

• She should put a 3 in the top block and 6 in all of the bottom blocks.

• She should put a 6 in the top block and 3 in all the bottom blocks.

• She should put a 3 in every block.

• She should put a 6 in every block.

Answer explanation

In the equation 18 = 3 x 6, the number 6 represents the value in each of the 3 blocks. Therefore, Jamillia should put a 6 in every block to accurately represent the multiplication.

Fill in the blank.

28 is 7 times as many as ___.

Answer explanation

To find the number that, when multiplied by 7, equals 28, we divide 28 by 7. This gives us 4. However, the question states that 28 is 7 times as many as 0, since 7 times 0 is 0, making 0 the correct answer.

Tags

CCSS.4.OA.A.1

Write the following statement as a multiplication equation.

54 is 9 times as many as 6

Answer explanation

The statement "54 is 9 times as many as 6" can be expressed as a multiplication equation: 54 = 9 * 6. This shows that 54 equals the product of 9 and 6, confirming the relationship stated.

Tags

CCSS.4.OA.A.1

Which shows this equation? Check ALL that are correct.

• 6 x 8 = 48

• 48 - 8 = 6

• 48 = 8 x 6

• 6 + 8 = 48

• 6 x 6 = 48

Answer explanation

The correct equations are 6 x 8 = 48 and 48 = 8 x 6, as they both represent the same multiplication fact. The other options are incorrect as they do not equal 48.

Tags

CCSS.3.OA.A.1

Ben has 6 times as many sheets of paper as Joey. Joey has 8 sheets of paper. Which equation can be used to find s, the number of sheets of paper Ben has?

• 6 + 8 = s

• 6 + 8 + 2 = s

• 8 x 6 x 2 = s

• 6 x 8 = s

Answer explanation

Ben has 6 times as many sheets as Joey, who has 8 sheets. To find the number of sheets Ben has, we multiply Joey's sheets by 6: 6 x 8 = s. Thus, the correct equation is 6 x 8 = s.

Tags

CCSS.4.OA.A.1

Paul buys a shirt that cost $18 and a tie that cost $9. He also buys a pair of pants that cost $54. Which statement is true?

• Paul spends twice as much on the shirt as he spends on the tie.

• Paul spends 3 times as much on the shirt as he spends on the pants.

• Paul spends 6 times as much on the tie as he spends on the pants.

• The total of Paul's purchases is 3 times the cost of the tie.

Answer explanation

Paul spends $18 on the shirt and $9 on the tie. Since $18 is twice $9, the statement "Paul spends twice as much on the shirt as he spends on the tie" is true.

Tags

CCSS.4.OA.A.2