Topic 9 Test Adding / Subtracting Fractions
Quiz
•
Mathematics
•
5th Grade
•
Practice Problem
•
Hard
Standards-aligned
Lisa Yarbrough
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10 questions
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1.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
What is the sum of these fractions?
Answer explanation
To find the sum of the fractions, we need to add them together. If the fractions are such that they cancel each other out or sum to zero, the correct answer is 0. Thus, the sum of these fractions is 0.
Tags
CCSS.7.NS.A.1C
2.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
Answer explanation
To find the common denominator of \(\frac{3}{4}\) and \(\frac{5}{6}\), we determine the least common multiple (LCM) of 4 and 6, which is 12. Thus, the common denominator is 12.
3.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
Answer explanation
To add \(\frac{1}{3}\) and \(\frac{3}{5}\), find a common denominator, which is 15. Convert the fractions: \(\frac{1}{3} = \frac{5}{15}\) and \(\frac{3}{5} = \frac{9}{15}\). Now add: \(\frac{5}{15} + \frac{9}{15} = \frac{14}{15}\).
Tags
CCSS.5.NF.A.1
CCSS.5.NF.A.2
4.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
Answer explanation
To subtract the fractions \( \frac{7}{8} - \frac{1}{4} \), convert \( \frac{1}{4} \) to eighths: \( \frac{1}{4} = \frac{2}{8} \). Now, subtract: \( \frac{7}{8} - \frac{2}{8} = \frac{5}{8} \). The correct answer is \( \frac{5}{8} \).
Tags
CCSS.5.NF.A.1
CCSS.5.NF.A.2
5.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
Answer explanation
To simplify \( \frac{18}{24} \), divide both the numerator and denominator by their greatest common divisor, which is 6. This gives \( \frac{18 \div 6}{24 \div 6} = \frac{3}{4} \). Thus, the correct answer is \( \frac{3}{4} \).
6.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
Answer explanation
To find the common denominator of \(\frac{5}{9}\) and \(\frac{2}{3}\), we identify the least common multiple (LCM) of the denominators 9 and 3. The LCM is 9, but the smallest common denominator that works for both fractions is 18.
7.
FILL IN THE BLANK QUESTION
5 mins • 1 pt
Answer explanation
To add \(\frac{1}{4}\) and \(\frac{2}{3}\), find a common denominator, which is 12. Convert \(\frac{1}{4}\) to \(\frac{3}{12}\) and \(\frac{2}{3}\) to \(\frac{8}{12}\). Adding gives \(\frac{11}{12}\), not 0.
Tags
CCSS.5.NF.A.1
CCSS.5.NF.A.2
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