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QUIZ 1- PERMUTATIONS

Authored by Veronica Miranda

Mathematics

10th Grade

CCSS covered

Used 4+ times

QUIZ 1- PERMUTATIONS
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20 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of 5! ?

120

150

200

100

Answer explanation

The value of 5! (5 factorial) is calculated as 5 × 4 × 3 × 2 × 1, which equals 120. Therefore, the correct answer is 120.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Calculate 7! / 5!

42

50

60

35

Answer explanation

To calculate 7! / 5!, we simplify: 7! = 7 × 6 × 5!; thus, 7! / 5! = 7 × 6 = 42. Therefore, the correct answer is 42.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for permutations of n items taken r at a time?

n! / (n - r)!

n! + r!

n! * (n - r)

(n + r)! / n!

Answer explanation

The formula for permutations of n items taken r at a time is n! / (n - r)!. This represents the number of ways to arrange r items from a total of n, making the first choice from n, the second from (n-1), and so on.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many different ways can the letters in the word 'MATH' be arranged?

12

18

24

30

Answer explanation

The word 'MATH' has 4 distinct letters. The number of arrangements is calculated using the factorial of the number of letters: 4! = 4 × 3 × 2 × 1 = 24. Therefore, the correct answer is 24.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If you have 4 different books, how many ways can you arrange them on a shelf?

12

16

24

30

Answer explanation

To arrange 4 different books, use the factorial of the number of books: 4! = 4 × 3 × 2 × 1 = 24. Thus, there are 24 ways to arrange the books on a shelf, making the correct answer 24.

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is 0! equal to?

-1

1

1.5

0

Answer explanation

0! is defined as 1 in mathematics. This is a convention that helps in combinatorial calculations and ensures consistency in formulas involving factorials. Therefore, the correct answer is 1.

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How many ways can you select 2 toppings from 5 available toppings?

20

5

10

15

Answer explanation

To select 2 toppings from 5, use the combination formula C(n, k) = n! / (k!(n-k)!). Here, n=5 and k=2. Thus, C(5, 2) = 5! / (2!3!) = (5×4)/(2×1) = 10. Therefore, the correct answer is 10.

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