turunan fungsi

f '(x) = 10 sin (2x - 1)

f '(x) = - 10 sin (2x - 1)

f '(x) = 5 sin (2x - 1)

f '(x) = - 5 sin (2x - 1)

f '(x) = sin (2x - 1)

f ' (x) = 3 cos (4x)

f ' (x) = 12 cos (4x)

f ' (x) = 3 sin (4x)

f ' (x) = 12 sin (4x)

f ' (x) = - 12 cos (4x)

$$-\frac{3}{2}\sqrt{2}$$  

$$-\frac{1}{2}\sqrt{2}$$  

$$0$$  

$$\sqrt{2}$$  

$$3\sqrt{2}$$  

$$f'\left(x\right)=2\sin2x$$  

$$f'\left(x\right)=\frac{1}{2}\sin2x$$  

$$f'\left(x\right)=-\frac{1}{2}\sin2x$$  

$$f'\left(x\right)=-2\sin2x$$  

$$f'\left(x\right)=-4\sin2x$$  

$$15x^2+8x-6$$  

$$15x^2+8x$$  

$$15x^2$$  

$$15x^2-8x+6$$  

$$15x+8$$  

$$x^3+x^2–2$$  

$$x^3+2x^2–4$$  

$$2x^3+2x^2–4$$  

$$2x^3+2x^2–4x$$  

$$2x^3+2x^2–4x+1$$  

$$x^5-x^3+3x^2-3$$  

$$5x^4+3x^2+6x$$  

$$5x^4-3x^2+6x$$  

$$5x^4-3x^2-6x$$  

$$x^4-x^2+x$$  

$$12\left(3x^2+5\right)^3$$  

$$24x\left(3x^2+5\right)^3$$  

$$12x\left(3x^2+5\right)^3$$  

$$24\left(3x^2+5\right)^3$$  

(40x² – 30x)(2x – 5)⁶

6x(8x – 5)(2x – 5)⁵

6x(8x – 5)(2x – 5)⁶

12x(8x – 5)(2x – 5)⁵

12x(8x – 5)(2x – 5)⁶

$$\left(2x^2+x+1\right)^4$$  

$$5x\left(2x^2+x+1\right)^4$$  

$$\left(20x+1\right)\left(2x^2+x+1\right)^4$$  

$$\left(4x+1\right)\left(2x^2+x+1\right)^4$$  

$$\left(20x+5\right)\left(2x^2+x+1\right)^4$$