HMH Unit 1 Algebra

for inequalities though – if you multiply or divide by a negative number, you must _________ the inequality sign.

• flip

• =

• subract

• add

Solve for x: 6 + x = 9

• x = 3

• x = 15

• x = 5x

• x = -3

Solve for x: x + 6 ≥ 9

• x ≥ 3

• x ≥ 15

• x ≥ -3

• x ≤ 15

To solve x + 6 = 9, my strategy will be to . . . (select all that apply)

• remove the "x" by subtracting it from both sides

• find a way to move everything except "x", to the other side of the "=" sign

• remove the +6 from the "x" side of the "=" sign by subtracting it from both sides

• remove the +9 by subtracting it from both sides

Solve for x: -x + 6 = 9

• -x = 3

• x = -3

• -x = 15

• x = -15

To solve -x + 6 = 9 my strategy will be to . . . (select all that apply)

• find a way to move everything except "x" to the other side of the "=" sign

• first, remove the +6 from the "x" side of the "=" sign by subtracting 6 from both sides.

• second, remove the "-1" from the "x" side of the "=" sign by dividing both sides by "-1"

• have a final solution x = -3

Solve for x: -x + 6 ≥ 9

• -x ≥ 3

• -x ≥ 15

• x ≤ 3

• x ≤ -3

To solve -x + 6 ≥ 9 my strategy will be to . . . (select all that apply)

• find a way to move everything except "x" to the other side of the "≥" sign

• first, remove the +6 from the "x" side of the "≥" sign

• second, remove the "-1" from the "x" side of the "=" sign by dividing both sides by "-1"

• third, since I need to solve for "x" by dividing both sides by a negative, I will FLIP the inequality sign the other way.

• have a final solution x ≤ -3

Distribute and solve for x: 3(x + 5) ≤ 2(5 - x)

• 5x ≤ -5

• x ≤ -1

• 3x ≤ -5 - 2x

• -x ≥ 5

Distribute and solve for x: 4(3 - x) + 2(x - 8) < 3x + 5

• -5x < 9

• x < -9/5

• x > -9/5

• -x < 9/5