Constraints and Objective Functions

Constraints and Objective Functions

10th - 11th Grade

16 Qs

quiz-placeholder

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Constraints and Objective Functions

Constraints and Objective Functions

Assessment

Quiz

Mathematics

10th - 11th Grade

Hard

Created by

Barbara White

FREE Resource

16 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

It is a method for finding a maximum or minimum value of some quantity, given a set of constraints.

Operations research

Maximization

Minimization

Linear programming

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

In other words...what are the vertices of the feasible region?

(0, 0), (0, 6), (6, 2), (8, 0)

(0, 0), (6, 0), (2, 6), (0, 8)

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

When graphing constraints, what do you call the area where all the shading overlaps?

the answer

the feasible region

the void

the objective function

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

Given the objective function: P = 30x + 50y

Which vertex maximizes the profit?

(0,0)

(6,2)

(8,0)

(0,6)

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image
Find the values of x and y that maximize the objective function P = 3x + 2y for the graph. What is the maximum value?
   
maximum value at (5, 4); 32
maximum value at (0, 8); 16
maximum value at (9, 0); 27
maximum value at (0, 0); 0

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

(7,4)

(3,10)

(10,1)

(8,5)

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A farmer can plant up to 6 acres of land with soybeans and corn. Her use of a necessary pesticide is limited by federal regulations to 15 gallons for her entire 6 acres. Soybeans require 2 gallons of pesticide for every acre planted and corn requires 3 gallons per acre. The profit the farmer makes by earning $4,000 for every acre of soybeans he plants and $3,000 for every acre he plants with barley can be modeled by P=4000x+3000y .  If x represents acres of soybeans and y represents acres of corns, which inequalities represent the possible solutions to her situation?
x≥0
y≥0
x+y≥6 
3x+2y≥15
x≥0 
y≥0 
x+y≤6
2x+3y≤15
x≥0 
y≥0 
4000x+y≤6
2x+600y≤15
P=4000x+3000y

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