Linear Quadratic Systems Substitution

When solving linear-quadratic systems algebraically, which method will we be using?

• Substitution
• Elimination
• Graphing
• Quadratically

Which of the following equations could be used to solve:
y = x² + 3x - 5
y = x + 3

• x² - 3x + 5 = x - 3
• x² + 3x - 5 = x + 3
• x² + 3x - 5 + x + 3 = 0
• x² + 3x - 5 = 0

Given the system 
y = x² + 3x - 5
y = x + 3
Write the substitution equation (x² + 3x - 5 = x + 3) in standard form.

• x² + 4x - 2 = 0
• x² - 2x + 8 = 0
• x² + 2x - 8 = 0
• x² + 4x - 8 = 0

Which method would be best to solve the equation (x² + 2x - 8 = 0) in standard form?

• Factoring
• Quadratic Formula
• Substitution
• Elimination

What are the factor of x² + 2x - 8?

• (x + 4)(x + 2)
• (x - 4)(x - 2)
• (x - 4)(x + 2)
• (x + 4)(x - 2)

What are the solutions to the equation x² + 2x - 8 = 0?

• x = -4 and x = 2
• x = 4 and x = 2
• x = 4 and x = -2
• x = -4 and x = -2

Given the system of equations:
y = x² + 3x - 5
y = x + 3
When x = -4, what is the value of y?

• -1
• 1
• 7
• -33

Given the system of equations:
y = x² + 3x - 5
y = x + 3
When x = 2, what is the value of y?

• 6
• -1
• 5
• -5

What are the solutions to the system:
y = x² + 3x - 5
y = x + 3

• (-4, 2) and (-1, 5)
• (-4, -1) and (2, 5)
• (2, -1 and (-4, 5)
• (-4, 1) and (2, -1)

Find the solution:
y = x² - 4x + 6
y = x + 2

• (3, 1) and (6, 4)
• (-1, 1) and (4, 2)
• (1, 3) and (4, 6)
• (1, 4) and (3, 6)