Factoring Trinomials With Leading Coefficients

One of the factors of

3v² - 4v - 7 is

• (3v-7)

• (v-7)

• (3v+1)

• (v-1)

Factor
3a² + 4a + 1

• (7a-10)(a-8)
• Not factorable
• (3a+1)(a+1)
• (3a-1)(a-1)

The factored form of
9x²-6x-8

Will be (ax+b)(cx+d) which statement is true about the values in the brackets?

• a and c are both equal to 3

• b and d are both negative values

• a is 9 and c is 1

• b is 4 and d is -2

Factor:
5x² + 17x + 6   

• (5x + 3)(x + 2) 
• (5x + 2)(x + 3) 
• (5x + 1)(x + 6) 
• (5x + 6)(x + 1) 

One method of factoring
6x² – 19x – 7  is to start by considering which two numbers will

• multiply to equal -7 and add to equal -19

• multiply to equal 42 and add to equal -19

• multiply to equal -42 and add to equal -19

• multiply to equal -19 and add to equal -7

The completely Factored form of
8n²-34n-30 is

• (n-5)(8n+6)

• 2(4n-5)(n-3)

• (2n-10)(4n-3)

• 2(n-5)(4n+3)

Factor:
 2m² + 3m - 9

• 2(m + 3)(m - 3)
• (2m - 3)²
• (m + 3)(2m - 3)
• (2m + 3)(m - 3)

In factored form  6x² + 5x - 6

is equal to (ax-b)(cx+d) where a, b, c, and d, are whole numbers.

Which is correct?

• b and d are both equal to 3

• a and b are both equal to 3

• b and c are both equal to 3

• a and d are both equal to 3