Diagnostic Exam Conics Precalculus

The endpoints of a diameter of a circle are (-4,1) and (2,5). Find the center and radius of the circle.

Tags

CCSS.HSG.GPE.A.1

Identify the conic from the equation: y² -4x -2y -2 = 0

• circle

• ellipse

• parabola

• hyperbola

Tags

CCSS.HSG.GPE.A.1

Find the center and radius of the circle: (x+2)² + (y-4)² =16

• center: (-2, 4); r = 4

• center: (2, -4); r = 4

• center: (-2, -4); r = 8

• center: (-2, 4); r = 16

Tags

CCSS.HSG.GPE.A.1

Identify the conic from the equations: 4x² -15y² + 6x - 8y -72 = 0

• circle

• ellipse

• parabola

• hyperbola

Tags

CCSS.HSG.GPE.A.1

A circle with a center of (-4, 5) passes through the point (2,3). What is the equation in standard form?

• (x-4)² + (y+5)² = 40

• (x-4)² + (y+5)² = 20

• (x+4)² + (y-5)² = 40

• (x-4)² + (y-5)² = 20

Tags

CCSS.HSG.GPE.A.1

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Tags

CCSS.HSG.GPE.A.1

Write the equation of the ellipse in standard form.

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Tags

CCSS.HSG.GPE.A.1

Convert the equation x² + 4y² + 2x + 24y + 21 = 0 into standard form.

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Tags

CCSS.HSG.GPE.A.1

Find the equation of the parabola with vertex (4,6) and focus (4,9).

• (x-4)² = 12(y - 6)

• (x-4)² = 3(y - 6)

• (y-6)² = 3(x-4)

• (y-6)² = 12(x-4)

Write the equation for the parabola.

• (y-2)² = -4(x-3)

• (y-2)² = -16(x-3)

• (x-3)² = -4(y-2)

• (x-3)² = -16(y-2)