Solutions to Quadratics Square

• -2, 4
• -8
• ±8
• No real solution

• -4, 2
• -2, 4
• -16
• -4

Determine the values of
a, b, and c for
the quadratic equation: 
4x² – 8x = 3

• a = 4, b = -8, c = 3
• a = 4, b =-8, c =-3
• a = 4, b = 8, c = 3
• a = 4, b = 8, c = -3

Find the zeros of this quadratic.

• b=4/5, b=3
• b=4, b=-3
• b=1/5, b=3
• b=4/5, b=-3

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property
• Yes, she factored correctly and then square rooted.
• No, she did factor correctly, but she can't use the zero product property as shown.
• No, she didn't factor correctly so the rest of her work is wrong. 

9k² = 225

• 4
• 4, -4
• 25, -25
• -5, 5

Solve the quadratic equation by factoring
a² + 10a + 21 = 0

• ± √21
• -3 , -7
• 3 , 7
• 28 , -7

Solve
4m² - 100 = 0

• m=25, -25
• m=96
• m=5, -5
• m=-96

What should you do first in solving this equation?
x² + 6x - 13 = 3

• Get factored form
• Write down: a=1, b=6, c=-13
• Make it equal 0 by subtracting 3 on each side
• Type it all in a calculator.

In the equation
y = x² +5x +7, match each leading coefficient with its correct letter 

• a=0, b=5, c=7
• a=1, b=5, c=7
• a=7, b=5, c=1