Finding Equivalent Fractions by Multiplying and Dividing

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{5}{7} = \frac{10}{14} = \frac{15}{21} = \frac{20}{28} = \frac{}{35}\)

Answer explanation

The missing equivalent fraction is \frac{25}{35} because each numerator is multiplied by 5 to get the next numerator, following the pattern.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{1}{3} = \frac{}{9} = \frac{5}{15} = \frac{7}{21} = \frac{9}{27}\)

Answer explanation

The missing equivalent fraction is 3/9. To find the missing numerator, multiply the denominator by the whole number in the pattern.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{9}{2} = \frac{18}{4} = \frac{27}{6} = \frac{36}{8} = \frac{}{10}\)

Answer explanation

The missing equivalent fraction is \frac{45}{10} because each numerator is multiplied by 9 and the denominator is multiplied by 2 in each step.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{8}{5} = \frac{16}{10} = \frac{24}{15} = \frac{}{20} = \frac{40}{25}\)

Answer explanation

The missing equivalent fraction is 32/20. Each numerator is obtained by multiplying the previous numerator by 2, and the denominator is increased by 5 each time.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{1}{6} = \frac{}{12} = \frac{3}{18} = \frac{4}{24} = \frac{5}{30}\)

Answer explanation

The missing equivalent fraction is 2/12. Each subsequent fraction is obtained by multiplying the numerator and denominator by the next consecutive number starting from 2.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{2}{3} = \frac{6}{9} = \frac{10}{15} = \frac{}{21} = \frac{18}{27}\)

Answer explanation

To find the missing equivalent fraction, continue the pattern by multiplying the numerator and denominator by 3. Therefore, the missing fraction is 15/21.

Tags

CCSS.3.NF.A.3A

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{7}{4} = \frac{14}{8} = \frac{21}{12} = \frac{28}{16} = \frac{}{20}\)

Answer explanation

The missing equivalent fraction is \frac{35}{20}. Each numerator is obtained by multiplying the previous numerator by 7, and the denominator is increased by 4 each time.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \(\frac{3}{8} = \frac{6}{16} = \frac{9}{24} = \frac{}{32} = \frac{15}{40}\)

Answer explanation

The missing equivalent fraction is \frac{12}{32}. Each numerator is multiplied by 3 to get the next equivalent fraction.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \[ \frac{1}{9} = \frac{2}{18} = \frac{3}{27} = \frac{4}{36} = \frac{5}{\_\_} \]

Answer explanation

The missing equivalent fraction is 45, so the pattern continues as [ \frac{5}{45} ]. Each numerator is multiplied by the same number to get the denominator.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1

Read the pattern and find the missing equivalent fraction in each problem. \[ \frac{7}{3} = \frac{14}{6} = \frac{21}{9} = \frac{28}{12} = \frac{35}{\_\_} \]

Answer explanation

The missing equivalent fraction is 42/18. Each numerator is multiplied by 7, and each denominator is multiplied by 3 to get the next fraction.

Tags

CCSS.3.NF.A.3B

CCSS.4.NF.A.1