Quadratics Story Problem

Quadratics Story Problem

9th Grade

9 Qs

quiz-placeholder

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Quadratics Story Problem

Quadratics Story Problem

Assessment

Quiz

Mathematics

9th Grade

Hard

Created by

Barbara White

FREE Resource

9 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What will be the object's maximum height?

2 ft

80 ft

144 ft

5 ft

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What time will be the object reach it's maximum height?

2 s

80 s

144 s

5 s

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet high. Its height is represented by the equation s(t) = –16t2 + 64t + 80. What time will the object reach the ground?

2 s

80 s

144 s

5 s

4.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

The quadratic equation f(x) = -16t2 + 64t models the height of a golf ball in feet over time in seconds. How long was the ball moving through the air?

10 seconds

8 seconds

6 seconds

4 seconds

5.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

The quadratic equation f(x) = -16t2 + 64t models the height of a golf ball in feet over time in seconds. What is the height of the ball after exactly 1 second?

28 ft

48 ft

60 ft

64 ft

6.

MULTIPLE SELECT QUESTION

3 mins • 1 pt

The quadratic equation f(x) = -16t2 + 64t models the height of a golf ball in feet over time in seconds. At what time is the ball exactly 64 feet above the ground?

6 seconds

4 seconds

2 seconds

1 second

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A diver is standing on a platform above the pool. He jumps form the platform with an initial upward velocity of 8 ft/s. Use the formula

h(t) = −16t2 + 8t + 24, where h is his height above the water, t is the time, v is his starting upward velocity, and s is his starting height. How high is the platform?

.25 ft

24 ft

25 ft

8 ft

8.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A diver is standing on a platform above the pool. He jumps from the platform with an initial upward velocity of 8 ft/s. Use the formula

h(t) = −16t2 + 8t + 24, where h is his height above the water, t is the time. What is the maximum height the diver reaches?

.25 ft

24 ft

25 ft

8 ft

9.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

A diver is standing on a platform above the pool. He jumps from the platform with an initial upward velocity of 8 ft/s. Use the formula

h(t) = −16t2 + 8t + 24, where h is his height above the water, t is the time. At what time will the diver reach the water?

.25 seconds

.75 seconds

1 second

1.5 seconds