Defining, Comparing, Identifying Functions

Defining, Comparing, Identifying Functions

9th Grade

53 Qs

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Defining, Comparing, Identifying Functions

Defining, Comparing, Identifying Functions

Assessment

Quiz

Mathematics

9th Grade

Practice Problem

Hard

CCSS
HSF.LE.A.2, HSF.BF.A.2, HSF.IF.A.2

+16

Standards-aligned

Created by

Barbara White

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53 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The table below represents the function F. The equation that represents this function is

F(x) = 3x

F(x) = 3x

F(x) = 2x + 1

F(x) = 2x + 3

Tags

CCSS.HSF.LE.A.2

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

The range of the function defined as y = 5x is

y < 0

y > 0

y ≤ 0

y ≥ 0

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If f(x)=3x and g(x)= 2x + 5, at which value of x is f(x) < g(x) ?

-1

2

-3

4

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The graph of the equation y=ax2 is shown below.

wider and opens downward

wider and opens upward

narrower and opens downward

narrower and opens upward

Tags

CCSS.HSF-IF.C.7A

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Media Image

The table below shows the average yearly balance in a savings account where interest is compounded annually. No money is deposited or withdrawn after the initial amount is deposited.

Which type of function best models the given data?

linear function with negative rate of change

linear function with positive rate of change

exponential decay function

exponential growth function

Tags

CCSS.HSF-LE.A.1A

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Krystal was given $3000 when she turned 2 years old. Her parents invested it at a 2% interest rate compounded annually. No deposits or withdrawals were made. Which expressions can be used to determine how much money Krystal had in the account when she turned 18?

3000(1 + 0.02)16

3000(1 - 0.02)16

3000(1 + 0.02)18

3000(1 - 0.02)18

Tags

CCSS.HSF.BF.A.2

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Mario's $15,000 car depreciates in value at a rate of 19% per year. The value, V, after t years can be modeled by the function V = 15,000(0.81)t. Which function is equivalent to the original function?

V = 15,000(0.9)9t

V = 15,000(0.9)2t

V = 15,000(0.9)t/9

V = 15,000(0.9)t/2

Tags

CCSS.HSA.APR.D.6

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