The program above:

• prints all the odd numbers between 1 and 20

• prints all even numbers between 1 and 20

• print all the odd numbers between 1 and 21

• prints all the even numbers between 1 and 21

How many times the following loop will execute:

i = 1

while True:

print(i)

i += 2

• 0

• 2,4,6,8,..................

• 1,3,5,7,9,.............

• 1,2,4,6,8......................

i = 1

while True:

if i%7 == 0:

break

print(i)

i += 1

• 123456

• 1234567

• error

• none

i = 1

while False:

if i%2 == 0:

break

print(i)

i += 2

• 1

• 1357......

• 1234......

• none of the mentioned

for i in range(10):

if i == 5:

break

else:

print(i)

else:

print("Here")

• 01234 Here

• 012345 Here

• 01234

• 12345

x = 'abcd'

for i in range(len(x)):

x = 'a'

print(x)

• a

• abcd abcd abcd

• a a a a

• none

The program above

• prints all the odd numbers between 1 and 20

• prints all even numbers between 1 and 20

• print all the odd numbers between 1 and 21

• prints all the even numbers between 1 and 21

The equivalent of the above for loop using the while syntax would be

• 
• 
• 
• 

The above program prints

• Numbers 1 to 10 in reverse order

• Numbers 1 to 11 in reverse order

• Numbers 1 to 10

• Numbers 1 to 11

The program above prints

• Numbers between 1 and 100 that are multiples of 5

• Numbers between 1 and 100

• Numbers between 1 and 100 divisible by 5

• Numbers between 1 and 101 that are multiples of 5