Solving via Substitution

Solve the system by substitution. 
y = 2x − 11 
2x − 8y = 4 

•  (6, 1)

• (6, −4)

• (6, −1)

• Infinite number of solutions  

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the proper way to set up the equation to begin solving via substitution?

• -2(-11) -3y= -7

• -2(6x-11) -3y = -7

• -2x - 3(11) = -7

• -2x - 3(6x-11)= -7

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve by substitution

y = 8x + 1

y = 6x + 3

• (1, 9)

• (4, 14)

• (0, 1)

• (2, 4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system by substitution. 
-2x - 2y = 16
y = -8

• (0, -8)

• (-8, 0)

• (-16, -8)

• (-16, -8)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• ( 1 , 0 )

• ( 0 , 1 )

• ( -1 , 0 )

• ( 0, - 1 )

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve this system by substitution.

• (1, -4)

• (1, 4)

• (-4, -7)

• (-7, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve using Substitution:
6x + 2y = -20
y = -2x - 4

• (-5, -14)

• (1, 6)

• (-6, 8)

• (2, -8)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• ( -1, 1 )

• ( 1, -1 )

• ( -1 , -1 )

• ( 1 , 1 )

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

solve by substitution: y=3x+14
y=-4x

• y=3

• y=1

• y= - 2

• y=4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to this system? Solve by substitution.
y= 4x + 3
2x - 3y = 21

• (3,-9)

• (-3,-9)

• (-3,9)

• (0,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6