Solving Square Roots

• Only x=5 is a solution since x=0 is extraneous.

• Only x=0 is a solution since x=5 is extraneous.

• Both are solutions.

• There is no solution.

Tags

CCSS.HSA.REI.A.2

Lauren tried to solve the radical equation.

Carefully look at her steps.

Which conclusion below is CORRECT?

• Only x = 2 is a solution.

• Only x = -1 is a solution.

• She didn't expand correctly after squaring both sides.

• She didn't factor correctly.

Tags

CCSS.HSA.REI.A.2

• x = -14

• x = 14

• No Solution

• x = 28

Tags

CCSS.HSA.REI.A.2

• x = 3

• x = -9

• x = -5/3

• x = 9

Tags

CCSS.HSA.REI.A.2

Tags

CCSS.HSA.REI.A.2

Take a close look at the equation. A graph has been provided. Which statement is CORRECT CONCLUSION?

• Since there is a NEGATIVE in front of the square root, there will be NO SOLUTION.

• There is a solution at x=5

• There is a solution at x=0

• There are solutions at x=0 and x=5.

Tags

CCSS.HSA.REI.A.2

Solve by taking square roots: 3 + r² = 12

• r = 3, r = - 3

• r = -3

• r = 3

Tags

CCSS.HSA-REI.B.4B

Solve
(x+3)²-5 = 9

• ±√14 -3

• √14 - 3

• ±11

• ±5

Tags

CCSS.HSA-REI.B.4B

x² = 25

• x = -5

• x = 5i, x = -5i

• x = 5

• x = 5, x = -5

Tags

CCSS.8.EE.A.2

• {49,-49}

• {8,-8}

• {7,-7}

• No Solution

Tags

CCSS.8.EE.A.2