Approximating Areas with Riemann Sums

Quiz
•
Mathematics
•
12th Grade
•
Hard
Anthony Clark
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 2 pts
What is the primary purpose of using Riemann sums in numerical integration?
To approximate the area under a curve
To find the exact value of an integral
To solve differential equations
To calculate the derivative of a function
2.
MULTIPLE CHOICE QUESTION
1 min • 2 pts
Which of the following is true about Riemann sums?
They can approximate the area under a curve by summing the areas of rectangles.
They can only be used with continuous functions.
They provide an exact value for the area under a curve.
They are more accurate than the Trapezoidal Rule and Simpson's Rule for all functions.
3.
MULTIPLE CHOICE QUESTION
1 min • 2 pts
It is an approximate area of a region, obtained by adding up the areas of multiple simplified slices of the region.
Riemann sum
definite integral
summation notation
sum of a series
4.
MULTIPLE CHOICE QUESTION
1 min • 2 pts
What does this picture represent?
Left Riemann Sum
Middle Riemann Sum
Right Riemann Sum
Trapezoidal Sum
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
A Riemann Sum uses rectangles to
approximate the area under a curve. The more rectangles, the better the approximation.
approximate the area under a curve. The less rectangles, the better the approximation.
approximate the area under a curve. The more rectangles, the worse the approximation.
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Riemann Sum uses rectangles to
approximate the area under a curve. The more rectangles, the better the approximation.
approximate the area under a curve. The less rectangles, the better the approximation.
approximate the area under a curve. The more rectangles, the worse the approximation.
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Based on the table, use a Right Riemann sum and 4 sub-intervals to estimate the Area under the curve. (Choose the correct set-up.)
5(3) + 1(4) + 2(5) + 1(7)
5(4) + 1(5) + 2(7) + 1(6)
5(3) + 6(4) + 8(5) + 9(7)
0(3) + 5(4) + 6(5) + 8(7)
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