Solving System of Equations with Multiplication

Authored by Anthony Clark

Mathematics

9th Grade

Solving System of Equations with Multiplication

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve the system using Multiplication.
2x + 3y = 12
5x - y = 13

x = -3, y = -2

x = 1.5, y = 2

x = 6, y = 0

x = 3, y = 2

MULTIPLE CHOICE QUESTION

1 min • 12 pts

Solve for x and y
3x + 2y = 16
7x + y = 19

(-2,5)

(-2,-5)

(2,-5)

(2,5)

DRAG AND DROP QUESTION

1 min • 5 pts

In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4( (a) )-2 (b) =-6
36- (c) y-2y= (d)
36- (e) =-6

9-3y

-6

14y

10y

x+3y

24y

DRAG AND DROP QUESTION

1 min • 2 pts

In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4(9-3y)-2y =-6
36-12y-2y=-6
36-14y =-6
-14y= (a)
y= (b)

-42

-3

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the solution:
2x-5y=15
3x+y=31

(10,1)

(13, -8)

(-10,-7)

No Solution

MULTIPLE CHOICE QUESTION

1 min • 1 pt

−6x + 6y = 0
9x − 8y = 4

(4, −9)

Infinite number of solutions

(−9, 4)

(4, 4)

REORDER QUESTION

1 min • 5 pts

Put the steps for solving by ELIMINATION in order:

Solve for the remaining variable

Make sure the equations are lined up

Multiply one or both equations by a number to get common but opposite coefficients

Subtract the equations to eliminate one variable

Plug that number into either original equation and solve for the other variable

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Solving System of Equations with Multiplication

Solve the system using Multiplication.
2x + 3y = 12
5x - y = 13

Solve for x and y
3x + 2y = 16
7x + y = 19

In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4( (a) )-2 (b) =-6
36- (c) y-2y= (d)
36- (e) =-6

In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4(9-3y)-2y =-6
36-12y-2y=-6
36-14y =-6
-14y= (a)
y= (b)

Find the solution:
2x-5y=15
3x+y=31

−6x + 6y = 0
9x − 8y = 4

Put the steps for solving by ELIMINATION in order:

Consider the system
4x+3y=-1
5x+4y=1
Let's say I want to eliminate the y's. What is the least common multiple of 3 and 4?
LCM = (a)
Multiply each equation by a number so that the coefficient of y will be 12, with one positive and one negative.
(b) (4x+3y=-1)
(c) (5x+4y=1)

Consider the system
4x+3y=-1
5x+4y=1
After we do this multiplication, what will the new equations be?
4(4x+3y=-1) ---> (a) x + (b) y= (c)
-3(5x+4y=1) ---> (d) x - (e) y= -3

Consider the system:
4x+3y=-1
5x+4y=1
Which we converted to:
16 x + 12y=-4
-15x - 12y= -3
Combining the equations straight down gives us:
(a) x+ (b) y= (c)
Solving for x, we get x= (d)

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Solving System of Equations with Multiplication

Solve the system using Multiplication. 2x + 3y = 125x - y = 13

Solve for x and y3x + 2y = 167x + y = 19

In this systemx+3y=94x-2y=-6it'll be easiest to start by solving the first equation for x.The result of doing so is x=​9-3y.Fill in the blanks to plug that expression in and solve for y:4(​ (a) )-2​ (b) =-636-​ (c) y-2y=​ (d) 36-​ (e) =-6

In this systemx+3y=94x-2y=-6it'll be easiest to start by solving the first equation for x.The result of doing so is x=​9-3y.Fill in the blanks to plug that expression in and solve for y:4(​9-3y)-2​y =-636-​12y-2y=​-636-​14y =-6-14y=​ (a) y=​ (b)

Find the solution:2x-5y=153x+y=31

−6x + 6y = 09x − 8y = 4

Put the steps for solving by ELIMINATION in order:

Consider the system4x+3y=-15x+4y=1Let's say I want to eliminate the y's. What is the least common multiple of 3 and 4?LCM = ​ (a) Multiply each equation by a number so that the coefficient of y will be 12, with one positive and one negative.​ (b) (4x+3y=-1)​ (c) (5x+4y=1)

Consider the system4x+3y=-15x+4y=1After we do this multiplication, what will the new equations be?​ 4(4x+3y=-1) ---> ​ (a) x +​ (b) y=​ (c) ​-3(5x+4y=1)​ ---> ​ (d) x -​ (e) y= -3

Consider the system:4x+3y=-15x+4y=1Which we converted to:16 x +​ 12y=​-4-15x -​ 12y= -3Combining the equations straight down gives us:​ (a) x+​ (b) y=​ (c) Solving for x, we get x=​ (d)

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Solve the system using Multiplication.
2x + 3y = 12
5x - y = 13

Solve for x and y
3x + 2y = 16
7x + y = 19

In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4( (a) )-2 (b) =-6
36- (c) y-2y= (d)
36- (e) =-6

In this system
x+3y=9
4x-2y=-6
it'll be easiest to start by solving the first equation for x.
The result of doing so is x=9-3y.
Fill in the blanks to plug that expression in and solve for y:
4(9-3y)-2y =-6
36-12y-2y=-6
36-14y =-6
-14y= (a)
y= (b)

Find the solution:
2x-5y=15
3x+y=31

−6x + 6y = 0
9x − 8y = 4

Consider the system
4x+3y=-1
5x+4y=1
Let's say I want to eliminate the y's. What is the least common multiple of 3 and 4?
LCM = (a)
Multiply each equation by a number so that the coefficient of y will be 12, with one positive and one negative.
(b) (4x+3y=-1)
(c) (5x+4y=1)

Consider the system
4x+3y=-1
5x+4y=1
After we do this multiplication, what will the new equations be?
4(4x+3y=-1) ---> (a) x + (b) y= (c)
-3(5x+4y=1) ---> (d) x - (e) y= -3

Consider the system:
4x+3y=-1
5x+4y=1
Which we converted to:
16 x + 12y=-4
-15x - 12y= -3
Combining the equations straight down gives us:
(a) x+ (b) y= (c)
Solving for x, we get x= (d)