Calculate the Margin of Error

For a class project, a student in a statistics class surveys the monthly rent for 32 unfurnished one-bedroom apartments in Boston and finds the mean monthly rent to be $1400 with a standard deviation of $220. Find the margin of error for the sample mean. (assuming 95% confidence) Round to the nearest hundredth

• $76.23

• $4.31

• $188.78

• $494.97

Researchers want to estimate with 95% confidence the true mean pulse rate of American adult males who jog at least 15 miles per week. They survey 21 males and find the sample mean pulse rate to be 52.6 beats per minute and a standard deviation of 3.22 beats per minute. Find the margin of error for the mean pulse rate of all American adult males who jog at least 15 miles per week. Round to the nearest tenth.

• 1.4 beats per minute

• 1.7 beats per minute

• 0.9 beats per minute

• 4.1 beats per minute

The operations manager of a large production plant wants to estimate the mean amount of time a worker takes to assemble a new electric component. Assume the standard deviation of the assembly time is 3.6 minutes. After observing 120 workers, the manager found their mean assembly time to be 16.2 minutes. What is the margin of error for a 99% confidence interval. Round to the nearest hundredth.

• 0.846

• 0.679

• 0.747

• 0.462

The operations manager of a large production plant wants to estimate the mean amount of time a worker takes to assemble a new electric component. Assume the standard deviation of the assembly time is 3.6 minutes. They sampled a group of 375 workers and found the mean to be 75 minutes. What is the margin of error for a 90% confidence interval? Round to the nearest thousandth

• 0.306

• 0.338

• 0.347

• 0.312

A sports analyst for an NBA team surveyed 50 games. The average points per game was 113 with a standard deviation of 5.6. Find the Margin of Error with 90% Confidence.

Identify the variables used in the Margin of Error formula

• 1.645

• Z

• 5.6

• n

• 50

A random sample of 40 bags of Doritos was obtained. The mean weight was 15.5 oz with a standard deviation of 0.2 oz. At a 95% confidence level, find the margin of error of the sample.

A high school randomly selected 75 of the 200 seniors at the school to take a sample college entrance exam. The mean grade point average (GPA) of the seniors selected was 2.85, and the standard deviation was 0.4. Select all of the statements that are true. Note: Margin of error \approx2\frac{s}{\sqrt{n}}, where s is the standard deviation and n is the sample size.

• The margin of error for the mean grade point average is about 0.057.

• The margin of error for the mean grade point average is about 0.092.

• The margin of error would decrease if the sample size were changed to 125 seniors.

• The margin of error would increase if the sample size were changed to 125 seniors.

A high school randomly selected 75 of the 200 seniors at the school to take a sample college entrance exam. The mean grade point average (GPA) of the seniors selected was 2.85, and the standard deviation was 0.4. Select all the statements that are true. (Note: Margin of error where s is the standard deviation and n is the sample size.)

• The margin of error for the mean grade point average is about 0.057

• The margin of error for the mean grade point average is about 0.092

• The margin of error would decrease if the sample size were changed to 125 seniors. 

• The margin of error would increase if the sample size were changed to 125 senior. 

4010 people were surveyed concerning their thoughts on the upcoming election. What was the margin of error?

At the Greenville County Cross Country Championships, a college scout took a sample of 20 runners. The average time was 17.25 minutes with a standard deviation of .03. Find the Margin of Error with 99% Confidence.

Identify the variables for the Margin of Error formula

• 20

• Z

• .03

• 2.58

• n