Solving for Unknowns

Solving for Unknowns

8th Grade

14 Qs

quiz-placeholder

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Solving for Unknowns

Solving for Unknowns

Assessment

Quiz

Mathematics

8th Grade

Practice Problem

Hard

CCSS
8.EE.C.8B, 6.EE.B.7, 6.EE.A.2B

+4

Standards-aligned

Created by

Anthony Clark

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14 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the value of x in the equation 9.3 + x = 42.8?

33.5

34.5

35.5

36.5

Tags

CCSS.6.NS.B.3

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Fill in the blank: In the equation X - 72 = 239, the value of X is ____.

A) 311

B) 312

C) 313

D) 314

Tags

TEKS.MATH.6.10A

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the value of x in the equation 1.2x = 27.6?

22

23

24

25

Tags

CCSS.6.EE.B.7

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

-52

-53

-54

-55

Tags

CCSS.6.EE.B.7

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve the following system of equations using the elimination method: 2x + 3y = 11 and 4x - 2y = 6

x = 2.5, y = 2

x = 2, y = 2.5

x = 5, y = 2

x = 2, y = 4

Answer explanation

To solve the system of equations, multiply the first equation by 2 to eliminate y. Then subtract the second equation from the first to find x. Substitute x back to find y. The correct solution is x = 2.5, y = 2.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Using the elimination method, solve the system of equations: 3x - 2y = 16 and 2x + 2y = 4

The solution is x = 4 and y = -2.

The solution is x = 0 and y = 0.

The solution is x = -3 and y = 5.

The solution is x = 2 and y = 3.

Answer explanation

By adding the two equations, we eliminate y, giving 5x = 20. Solving for x, we get x = 4. Substituting x back into one of the equations, we find y = -2. Therefore, the solution is x = 4 and y = -2.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Solve the following system of equations using the elimination method: 5x + 2y = 23 and 3x - 4y = -7

x = 3, y = 4

x = 4, y = 5

x = 2, y = 3

x = 5, y = 2

Answer explanation

To solve the system of equations, multiply the first equation by 2 and the second equation by 5 to eliminate y. Then, subtract the equations to find x = 3. Substitute x back to find y = 4. Therefore, x = 3 and y = 4.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

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