Solving for Unknowns

Quiz
•
Mathematics
•
8th Grade
•
Hard
Standards-aligned
Anthony Clark
FREE Resource
14 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the value of x in the equation 9.3 + x = 42.8?
33.5
34.5
35.5
36.5
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Fill in the blank: In the equation X - 72 = 239, the value of X is ____.
A) 311
B) 312
C) 313
D) 314
Tags
TEKS.MATH.6.10A
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the value of x in the equation 1.2x = 27.6?
22
23
24
25
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
-52
-53
-54
-55
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve the following system of equations using the elimination method: 2x + 3y = 11 and 4x - 2y = 6
x = 2.5, y = 2
x = 2, y = 2.5
x = 5, y = 2
x = 2, y = 4
Answer explanation
To solve the system of equations, multiply the first equation by 2 to eliminate y. Then subtract the second equation from the first to find x. Substitute x back to find y. The correct solution is x = 2.5, y = 2.
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Using the elimination method, solve the system of equations: 3x - 2y = 16 and 2x + 2y = 4
The solution is x = 4 and y = -2.
The solution is x = 0 and y = 0.
The solution is x = -3 and y = 5.
The solution is x = 2 and y = 3.
Answer explanation
By adding the two equations, we eliminate y, giving 5x = 20. Solving for x, we get x = 4. Substituting x back into one of the equations, we find y = -2. Therefore, the solution is x = 4 and y = -2.
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Solve the following system of equations using the elimination method: 5x + 2y = 23 and 3x - 4y = -7
x = 3, y = 4
x = 4, y = 5
x = 2, y = 3
x = 5, y = 2
Answer explanation
To solve the system of equations, multiply the first equation by 2 and the second equation by 5 to eliminate y. Then, subtract the equations to find x = 3. Substitute x back to find y = 4. Therefore, x = 3 and y = 4.
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