Solving Linear Equations by Substitution

• (2,-2)

• (-3,1)

• Infinitely many solutions

• No solution

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• No solution

• (-3,-3)

• Infinitely many solutions

• (-2,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (6,-2)

• (4,-8)

• Infinitely many solutions

• No solution

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (1,-1)

• Infinitely many solutions

• (3,4)

• No solution

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• No Solution

• (2, 2)

• (-1, 2)

• (-1, -2)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the first step in solving a system by Substitution?

• Make sure both equations are in standard form.

• Make sure at least one equation is solved for one variable.

• Make sure both equations are in slope-intercept form.

• Make sure both equations can be solved.

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• (1, -4)

• (1, 4)

• (-4, -7)

• (-7, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

• Infinite number of solutions

• (0, 7)

• (-5, -7)

• (5, 7)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

x = -3y - 8

x - 2y = -3

• (5, -1)

• (-5, 1)

• (-5,-1)

• (1,-5)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

x = 3y -13

4x + 2y = 4

• (1, 4)

• (-1, -4)

• (-1, 4)

• (1, -4)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6