Statistics Confidence Intervals and Significance Test

Statistics Confidence Intervals and Significance Test

12th Grade

15 Qs

quiz-placeholder

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Statistics Confidence Intervals and Significance Test

Statistics Confidence Intervals and Significance Test

Assessment

Quiz

Mathematics

12th Grade

Hard

Created by

Anthony Clark

FREE Resource

15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

At a baseball game, 42 of 65 randomly selected people own an iPod. At a rock concert occurring at the same time across town, 34 of 52 randomly selected people own an iPod. A researcher wants to test the claim that the proportion of iPod owners at the two events is different. A 90% confidence interval for the difference (Game - Concert) in populations proportions is (-0.154, 0.138). Which of the following gives the correct outcome of the researcher's test of the claim?

Because the interval includes 0, the researcher can conclude that the proportion of iPod owners at the two events is the same.

Because the center of the interval is -0.008, the researcher can conclude that a higher proportion of people at the rock concert own iPods than at the baseball game.

Because the interval includes 0, the researcher cannot conclude that the proportion of iPod owners at the two events is different.

Because the interval includes -0.008, the researcher cannot conclude that the proportion of iPod owners at the two events is different.

Because the interval includes more negative than positive values, the researcher can conclude that a higher proportion of people at the rock concert own iPods than at the baseball game.

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

0.90

0.40

0.05

0.20

0.10

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Conference organizers wondered whether posting a sign that says "Please take only one cookie" would reduce the proportion of conference attendees who take multiple cookies from the snack table during a break. To find out the organizers randomly assigned 212 attendees to take their break in a room where the snack table had a sign posted, and 189 attendees were assigned to a room where the snack table did not have a sign posted. In the room without a sign posted, 24.3% of attendees took multiple cookies. In the room with the sign posted, 17% of attendees took multiple cookies. Is this decrease in proportions statistically significant at the 5% level?

No, the P-value is 0.034

No, the P-value is 0.068

Yes, the P-value is 0.034

Yes, The P-value si 0.068

Cannot be determined from the information given.

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the critical z-score for a 94% confidence interval?

2.57

2.33

1.95

1.88

1.75

5.

MULTIPLE CHOICE QUESTION

1 min • 8 pts

To test the durability of cell phone screens, phones are dropped from a height of 1 meter until they break. A random sample of 40 phones was selected from each of two manufacturers. The phones in the samples were dropped until the screens broke. The difference in the mean number of drops was recorded and used to construct the 90 percent confidence interval (0.46, 1.82) to estimate the population difference in means. Consider the sampling procedure taking place repeatedly. Each time samples are selected, the phones are dropped and the statistics are used to construct a 90 percent confidence interval for the difference in means. Which of the following statements is a correct interpretation of the intervals?

Approximately 90 percent of the intervals will extend from 0.46 to 1.82.

Approximately 90 percent of the intervals constructed will capture the difference in sample means.

Approximately 90 percent of the intervals constructed will capture the difference in population means.

Approximately 90 percent of the intervals constructed will capture at least one of the sample means.

Approximately 90 percent of the intervals constructed will capture at least one of the population means.

6.

MULTIPLE CHOICE QUESTION

1 min • 8 pts

A two-sample t-test for a difference in means was conducted to investigate whether defensive players on a football team can bench-press more weight, on average, than offensive players. The conditions for inference were met, and the test produced a test statistic of t = 1.083 and a p-value of 0.15. Based on the p-value and a significance level of 5% , which of the following is the correct conclusion?

Reject the null hypothesis because 0.15 > 0.05. There is not convincing evidence that defensive players can bench-press more weight, on average, than offensive players.

B) Reject the null hypothesis because 0.15 > 0.05. There is convincing evidence that defensive players can bench-press more weight, on average, than offensive players.

C) Fail to reject the null hypothesis because 0.15 > 0.05. There is not convincing evidence that defensive players can bench-press more weight, on average, than offensive players.

D) Fail to reject the null hypothesis because 0.15 > 0.05. There is convincing evidence that defensive players can bench-press more weight, on average, than offensive players.

E) Fail to reject the null hypothesis because 0.15 > 0.05. There is convincing evidence that defensive players can bench-press the same amount of weight, on average, as offensive players.

7.

MULTIPLE CHOICE QUESTION

1 min • 8 pts

Animal researchers studying cows and horses conducted a two-sample t-test for a difference in means to investigate whether grazing cows eat more grass, on average, than grazing horses. All conditions for inference were met, and the test produced a test statistic of t = 1.664 and a p-value of 0.0487. Which of the following is a correct interpretation of the p-value?

The probability that cows eat more grass than horses, on average, is 0.0487.

The probability that cows eat the same amount of grass as horses, on average, is 0.0487.

Assuming that the mean amount of grass eaten by cows is greater than the mean amount of grass eaten by horses, the probability of observing a test statistic of at most 1.664 is 0.0487.

Assuming that the mean amount of grass eaten by cows is equal to the mean amount of grass eaten by horses, the probability of observing a test statistic of at most 1.664 is 0.0487.

Assuming that the mean amount of grass eaten by cows is equal to the mean amount of grass eaten by horses, the probability of observing a test statistic of at least 1.664 is 0.0487.

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