Substitution Method

Solve the system of equations by substitution.
y = -4x + 5
y =  3x - 16

• (-3, -25)

• (3,-7)

• (11, 17)

• (21, 47)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve using substitution.
x - 2y = 2
3x + 4y = 3

• (1.4, -0.3)

• (3.1, 5)

• (-2.5, 3.5)

• (6.9, 1.02)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

What is the solution to the system of equations? 
y = 3x - 8
y = 4 - x

• (3,1)

• (1,3)

• (-3,1)

• (3,-1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve for x and y using any method we've learned!
y = 2x + 1
y = 4x - 1

• (1,3)

• (-1,-3)

• (-1,3)

• (3,1)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Read each step of the Substitution method for solving a System of Equations. Then, match the result of performing the step with the step.

• 2(2) + y = 5

  y = 1

• Step 2: Substitute the expression in the other equation

• (2, 1)

• Step 5: Present the solution as an ordered pair

• -3x + 6(5-2x) = 0

• Step 4: Substitute the variable's value in the other equation; solve

• y = 5 - 2x

• Step 1: Solve one equation's variable (expression)

• x = 2

• Step 3: Solve the equation for a value

Tags

CCSS.MATH.CONTENT.HSA.REI.C.6

CCSS.MATH.CONTENT.HSA.CED.A.3

Solve the system by using the substitution method

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using the substitution method

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system using the substitution method:

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

solve by substitution: y=3x+14
y=-4x

• y=3

• y=1

• y= - 2

• y=4

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6

Solve the system of equations using substitution:
-4x + 4y = 8
y = -2x - 10

• (-4, -2)

• (12, -34)

• (4, -18)

• (-2, -6)

Tags

CCSS.8.EE.C.8B

CCSS.HSA.REI.C.6