Basics of Solving Exponential and Logarithmic Equations

• A
• B
• C
• D

• A
• B
• C
• D

3^{2x – 6}  = 81

• x = log 4

• x = 5

• x = 4

• x = -1

log₅ (2x - 3)² = 6

• x = 128

•  x = 64

• x = 4

• x = 14

Using the change of base rule, what is this logarithm equivalent to?

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• B

• C

• D

Solve the equation for x (hint: simplify first)

• 458.38

• 25

• 3,051,757,813

• -0.845

Re-write in log form 2⁶=64

• log₂6=64

• log₂64=6

• log₆₄2=6

• log₆₄6=2

Rewrite log_pt = m in exponential form.

• p^t = m

• t^m = p

• m^t = p

• p^m = t

Evaluate log_b(b)

• -1

• 0

• 1

• b

Evaluate.
3 log₂4

• 3

• 6

• 2

• 4