Solving Exponential and Logarithm

ln(x+8) - ln (8) = 3

• 152.68

• 188.77

• 4.24

• 8.01

Determine the correct set-up for: log₄(x-1) - log₄(x+7) = log₄6

• log₄(x-1)/(x+7)=log₄(6)

• log₄(x-1)(x+7)=log₄(6)

• log₄(x+7)/(x-1)=log₄(6)

• (x-1)(x+7)=6

Solve.

2(16^x+6) - 8 = 35

• -4.67

• -4.89

• -2.93

• -2.95

Tags

CCSS.HSF.LE.A.4

Solve:

log (x - 1) - log (x - 2) = log 5

• 7

• 4/9

• 9/4

• 1/7

Rewrite the exponential as a log.

2^3x+1 = 12

• ln(2)= 3x+1

• log₂(12)= 3x+1

• ln(6)=3x+1

• log₁₂(2)= 3x+1

Tags

CCSS.HSF.BF.B.5

log₂(x + 3)=5

• x=2

• x=29

• x=7

• x=32

Tags

CCSS.HSF.BF.B.5

Which is the correct way to rewrite,log₆(x-3)= 2, in order to solve.

• 6² = x-3

• 2⁶ = x - 3

• ln(2) = x-3

• e⁶ = x-3

Tags

CCSS.HSF.BF.B.5

log₈(6-5x) = log₈(3- 4x)

• x = 3

• No Solution

• x = 9

• x = 1

The first step to solve 8 + log 7 = 10 is...

• Rewrite exponentially

• Subtract 8 on both sides to isolate the log

• Divide by 7 on both sides

Determine the correct set-up for:

log(x) + log (x-9) = 18

• log(x)/(x-9)=18

• log(-7x)=18

• log(x)+(x-9)=18

• logx(x-9)=18