Solving Polynomial

Solve by Factoring:  4x² + 11x - 3 = 0

• x = -3/4 and x = -1

• x = 4 and x = 3

• x = 1/4 and x = -3

• x = -1/4 and x = 3

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 5)(x - 1) = 0

• { 5, 1 }

• { 5, -1 }

• { -5, 1 }

• { -5, -1 }

Tags

CCSS.HSA-REI.B.4B

Solve by Factoring:
x² + 15x + 64 = 20

• {-8, 2}

• {-7, 5}

• {-11, -4}

• {-11}

Tags

CCSS.HSA-REI.B.4B

Factor this difference of cubes:
x³ - 343

• (x + 7) (x² - 7x + 49)

• (x² + 1) (x - 343)

• (x - 7) (x² + 7x + 49)

• (x² - 343) (x + 1)

Tags

CCSS.HSA.APR.C.4

Find the quotient

Mathematical Equivalence

ON

Tags

CCSS.HSA.APR.D.6

• a = 0

• a = 2

• a = -2, 0

• a = 2, 0

Tags

CCSS.HSA-REI.B.4B

Solve x⁴ - 256 = 0

• x = 4, x = - 4

• x = 4, x = 4i

• x = 4, x -4, x = 4i

• x = 4, x -4, x = 4i,         x = -4i

Tags

CCSS.HSA-REI.B.4B

What are the solutions to the polynomial equation?
Choose ALL that apply.

• 2

• -2

• -3

• 3

Solve: -6x-1+5x²=8x²

• x = 5 ±√67 /6

• x = 1, 2/7

• x = 1 ±√ 22

• x = 3 ±√6 / -3

Tags

CCSS.HSA-REI.B.4B

Answer explanation

The roots of the polynomial equation can be found by factoring the equation as (x-1)(x+2)(x-3)=0. Therefore, x = 1, -2, 3.

Tags

CCSS.HSA-REI.B.4B